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3 years ago

(5x10-6) (4x10 - 6) =

Mathematics

2 answers:

uranmaximum [27]3 years ago

6 0

Answer:

1496

Step-by-step explanation:

hope this helps! Please mark brainliest

Monica [59]3 years ago

3 0

Answer:

1496

Step-by-step explanation:

Solve the equation and simplify

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Use the drop-down menus to compare −2.25 and −3.

Kisachek [45]

-2.5>-3 because the bigger a negative number is like -15,-18, etc the smaller it’s value actually gets so -2.5 is greater because it is closer to 0 on a number line.

5 0

3 years ago

Read 2 more answers

Karen is buying pens and pencils for the new school year. She wants to have no more than 25 writing utensils in all. She also wa

bezimeni [28]

For this case, the first thing we must do is define variables.
We have then:
x: number of pens
y: number of pencils
We now write the system of inequations:
$x + y \leq 25

y \geq (x - 3) ^ 2
$
The solution to the system of inequations is given by the shaded region.
Note: see attached image.

3 0

4 years ago

A sociologist was investigating the ages of grandparents of high school students. From a random sample of 10 high school student

umka2103 [35]

Answer:

$(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908$

$(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308$

So then the confidence interval for the difference of means is given by:

$-8.908 \leq \mu_M -\mu_F \leq 5.308$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_{M}= 69.8$ represent the mean for the age of grandmother

$\bar X_{F}= 71.6$ represent the mean for the age of grandfather

$s_{M}= 8.38$ represent the sample deviation for the age of grandmother

$s_{F}= 6.65$ represent the sample deviation for the age of grandfather

$n_M = n_F= 10$

Solution to the problem

For this case the confidence interval is given by:

$(\bar X_{M} -\bar X_F) \pm t_{\alpha/2} \sqrt{\frac{s^2_M}{n_M} +\frac{s^2_F}{n_F}}$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n_M +n_F-2=10+10-2=18$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,18)".And we see that $t_{\alpha/2}=2.101$

And replacing we got:

$(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908$

$(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308$

So then the confidence interval for the difference of means is given by:

$-8.908 \leq \mu_M -\mu_F \leq 5.308$

5 0

4 years ago

Write these numbers as fractions. Simplify the answers. 0.5, 12.3, 0.07, 0.625

motikmotik

0.5 => 5/10 => 1/2

12.3 => 123/10

0.07 => 7/100

0.625 => 625/1000 => 25/40 => 5/8

4 0

3 years ago

Read 2 more answers

How are comparisons between negative numbers different than comparisons between positive numbers?

lara [203]

On a number line, numbers always increase to the right and decrease to the left. Numbers to the right are greater than numbers to the left and numbers to the left are less than numbers to the right.

6 0

3 years ago