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2 years ago

13

PLEASE HELP! I NEED THE ANSWER SOON!

2 answers:

Wewaii [24]2 years ago

8 0

Answer:

6 * (m + n)

Step-by-step explanation:

Aliun [14]2 years ago

8 0

Answer:

Its the top 2 and the last one

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If a regression analysis shows an R factor of 0.15, it is safe to assume a perfect positive relationship between cost and volume

saw5 [17]

Answer:

a very weak relationship between cost and volume

Step-by-step explanation:

The R factor is used to access the strength of the relationship between a dependent and independent variable. The R factor ranges between - 1 and 1. With negative values depicting a negative linear relationship and positive values meaning a positive relationship. The closer the R factor is to - 1 or + 1, the greater the strength, a value of 0 means, no correlation exists.

Hence, a R factor of 0.15 depicts a positive but very weak relationship between cost and volume as the R value is close to 0.

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2 years ago

What is the domain and range of y=6

Ilya [14]

Answer:

domain -infinity

range(6)

Step-by-step explanation:

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3 years ago

The answer for the question I don't know how to slove it

katovenus [111]

You have to multiply and add!

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3 years ago

Is my answer correct !???

puteri [66]

Yes, your answer is correct.

5 0

3 years ago

Given that y is directly proportional to x^2 and that y=2 when x=3 find the value of y when x=6

Sergio039 [100]

Answer:y=4/3

y is directly proportional to x^2 is written as

$y \alpha {x}^{2}$ introducing a constant,

y=kx^2

but from the question, when y=2 , x=3 . putting it in the formula to get the value of k

$2 = {3}^{2} \times k$

2=9k . <em>divi</em><em>ding</em><em> </em><em>throu</em><em>gh</em><em> </em><em>by</em><em> </em><em>9</em><em> </em><em>to</em><em> </em><em>get</em><em> </em><em>the</em><em> </em><em>valu</em><em>e</em><em> </em><em>of</em><em> </em><em>k</em>

<em> $\frac{2}{9} = \frac{9k}{9}$ </em>

<em> $k = \frac{2}{9}$ </em>

<em>pu</em><em>tting</em><em> </em><em>it</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>ge</em><em>neral</em><em> </em><em>expres</em><em>sion</em>

<em> $y = \frac{2}{9} x$ </em>

<em>the</em><em> </em><em>valu</em><em>e</em><em> </em><em>of</em><em> </em><em>y</em><em> </em><em>whe</em><em>n</em><em> </em><em>x</em><em>=</em><em>6</em>

<em> $y = \frac{2}{9} \times 6$ </em>

<em> $y = \frac{4}{3}$ </em>

<em>there</em><em>fore</em><em> </em><em>the</em><em> </em><em>valu</em><em>e</em><em> </em><em>of</em><em> </em><em>y</em><em> </em><em>when</em><em> </em><em>x</em><em>=</em><em>6</em><em> </em><em>is</em>

<em>4</em><em>/</em><em>3</em>

3 0

3 years ago