Question

The presence of freckles is due to a dominant allele. Four percent of the individuals in a particular population lack freckles. Use the Hardy-Weinberg formula to calculate the percentage of individuals in this population who are homozygous dominant for freckles.
a) 32%
b) 80%
c) 64%
d) 20%
e) 4%

Answer 1

Answer:

Option C

Explanation:

Allele for dominant freckle trait is "F"

Allele for recessive no freckle trait is "f"

Given -

Population lacking freckles  $= 4$%

As per Hardy Weinberg's equilibrium equation

p represents the frequency of dominant allele in a given population and $p^2$ represents the frequency of dominant individuals in a given population

Like wise

q  represents the frequency of recessive allele in a given population and $q^2$ represents the frequency of recessive individuals in a given population

$q^2 = 0.04\\q = 0.2$

Frequency of dominant allele $= 1- 0.2\\= 0.8$

Frequency of homozygous recessive individual

$q^2 = 0.4$

Frequency of homozygous dominant individual

$q^2 = 0.4$$0.8^2\\= 0.64$

Option C is correct