100% of her middle school class = 56
200% of her middle school class = 112 (56 x 2)
25% of her middle school class = 14 (56/4)
225% of her middle school class = 126 (112 + 14)
There are 126 students in her high school class.
The simple interest earned in year 1 is 7.5. The simple interest earned in year 1 is $7.50. The total interest earned at the end of year 4 is $30.00
<h3>How to calculate a simple interest amount?</h3>
If the initial amount (also called as principal amount) is P, and the interest rate is R% annually, it is left for T years for that simple interest.
3% simple annual interest paid on $250
A 2-column table with 4 rows.
Column 1 is labeled Year with entries 1, 2, 3, 4.
Column 2 is labeled Total Interest Paid with an entries question mark, 15 dollars, 22 dollars, and 50 cents,
The simple interest earned in year 1 is calculated as
The first one is (0.03)(250) = 7.5
The simple interest earned in year 1 is
The second one is $7.50
The total interest earned at the end of year 4 is
The third one is $30.00
Learn more about interest here:
brainly.com/question/11897800
#SPJ1
Answer: 180 i think
Step-by-step explanation: .5*200+.2X=.3(200+X)
100+.2X=60+.3X
.2X-.3X=60-100
-.1X=-40
X=-40/-.1
X=400 OUNCES OF 20% COPPER.
PROOF
.5*200+.2*400=.3(200+400)
100+80=.3*600
100+80=180
180=180
Answer:
Step-by-step explanation:
The amplitude is 6, so A=6.
Also, the midline is y=-3, so C=-3.
The period is 10, so 2pi/k = 10 -> k=5.
Now we need to determine if this is a sine graph or a cosine graph. As the y-intercept is not the value of C, we can determine that this is a cosine graph, and thus y=6cos(5x)-3.
Let G be some point on the diagonal line away from point E.
Angle DEG represents angle 1.
We're given that angle DEF is a right angle which means it's 90 degrees. Angle DEG is some angle smaller than 90 degrees. By definition, that must mean angle 1 is acute. Any acute angle is smaller than 90 degrees. There's not much else to say other than this is just a definition problem.
----------------
Extra side notes:
If angle 1 was a right angle, then that would mean angle GEF would have to be 0 degrees; however the diagram shows this isn't the case.
If angle 1 was obtuse, then there's no way we'd be able to fit it into angle DEF. In other words, there's no way to have an angle larger than 90 fit in a 90 degree angle.