Bobby spent 122 minutes on school work the first week, but only spent 109 minutes on school work the second week.

PLZ HELP!!!! Choose all that are correct A: Random samples from the same population will vary from sample to sample.

kirill [66]

Answer:a,d

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

F(x) = 2(x+3)2 -7 a= h= k=

vlabodo [156]

Answer:

Step-by-step explanation:

In vertex form, the equation is

y = a(x-h)^2 + k

So just read off the values!

6 0

3 years ago

1. When Lucas dumped the coins out of his piggy bank, he noticed that there were only nickels and dimes, and the number of nicke

vaieri [72.5K]

1- The total value of the Lucas coins dumped out of his piggy bank was $ 5.

2- Franco dumped out 36 coins from his piggy bank (16 quarters and 20 nickels).

3- There is no possible solution, as neither combination gives a total of $ 10, which is the combined total of Lucas and Franco's coins.

1- Given that when Lucas dumped the coins out of his piggy bank, he noticed that there were only nickels and dimes, and the number of nickels was twice the number of dimes, to determine, if there were 50 nickels, what was the total value of the Lucas coins dumped out of his piggy bank, the following calculation must be performed:

Nickel = 0.05
Dime = 0.10
N + D = X
N + 1 / 2N = X
50 + 25 = 75
50 x 0.05 + 25 x 0.1 = X
2.50 + 2.50 = X
5 = X

Therefore, the total value of the Lucas coins dumped out of his piggy bank was $ 5.

2- Since when Franco dumped the coins out of his piggy bank, he noticed that there were only nickels and quarters, and the number of quarters was six more than half the number of nickels, to determine, if the total value of the coins Franco and Lucas dumped out of each piggy bank was the same, how many coins did Franco dump out of his piggy bank, the following calculation must be performed:

Nickel = 0.05
Quarter = 0.25
Q = 2N + 6
4 x 0.25 + 6 x 0.25 = 1 + 1.5 = 2.5
8 x 0.05 = 0.40
2.5 + 0.4 = 2.9
8 x 0.25 + 6 x 0.25 = 2 + 1.5 = 3.5
16 x 0.05 = 0.8
3.5 + 0.8 = 4.3
10 x 0.25 + 6 x 0.25 = 2.5 + 1.5 = 4
20 x 0.05 = 1
4 + 1 = 5
10 + 6 + 20 = 36

Therefore, Franco dumped out 36 coins from his piggy bank (16 quarters and 20 nickels).

3- Since when Callie dumped the coins out of her piggy bank, she noticed that there were only nickels, dimes and quarters, and the number of dimes was one more than twice the number of quarters, and there were half as many quarters as nickels, y the coins dumped out of Callie's piggy bank had a total value equal to that of the coins dumped out of Franco's and Lucas' piggy banks combined, to determine what was the total value of the nickels and dimes dumped out of Callie's piggy bank, the following calculation should be performed:

Nickel = 0.05
Dime = 0.10
Quarter = 0.25
(D + 1) + 1 / 2Q + N = 10
1 x 0.1 + 20 x 0.1 + 10 x 0.25 + 20 x 0.05 = 2.1 + 2.5 + 1 = 5.6
1 x 0.1 + 36 x 0.1 + 18 x 0.25 + 36 x 0.05 = 3.6 + 4.5 + 1.8 = 9.9
1 x 0.1 + 38 x 0.1 + 19 x 0.25 + 38 x 0.05 = 3.9 + 4.75 + 1.9 = 10.55

Therefore, there is no possible solution, as neither combination gives a total of $ 10, which is the combined total of Lucas and Franco's coins.

Learn more in brainly.com/question/11096797

6 0

2 years ago

Hello, can u help me out please i will give brainlist :)

aalyn [17]

Answer:

$5.75

Step-by-step explanation:

Find the difference between the weeks as this will give you the difference hence the amount deposited each week

0->1

is 12.00->17.75

diffrence is $5.75

1->2

is 17.75->23.50

diffrence is $5.75

the amount saved each week is $5.75

6 0

2 years ago

Find a formula for the inverse of the function f(x)=3x^3 + 2sinx + 4cosx

vitfil [10]

Explicit Functiony = f(x) is said to define y explicitly as a function of x because the variable y appears alone on one side of the equation and does not appear at all on the other side. (ex. y = -3x + 5)Implicit FunctionAn equation in which y is not alone on one side. (ex. 3x + y = 5)Implicit DifferentiationGiven a relation of x and y, find dy/dx algebraically.d/dx ln(x)1/xd/dx logb(x) (base b)1/xln(b)d/dx ln(u)1/u × du/dxd/dx logb(u) (base b)1/uln(b) × du/dx(f⁻¹)'(x) = 1/(f'(f⁻¹(x))) iff is a differentiable and one-to-one functiondy/dx = 1/(dx/dy) ify = is a differentiable and one-to-one functiond/dx (b∧x)b∧x × ln(b)d/dx e∧xe∧xd/dx (b∧u)b∧u × ln(b) du/dxd/dx (e∧u)e∧u du/dxDerivatives of inverse trig functionsStrategy for Solving Related Rates Problems1. Assign letters to all quantities that vary with time and any others that seem relevant to the problem. Give a definition for each letter.

2. Identify the rates of change that are known and the rate of change that is to be found. Interpret each rate as a derivative.

3. Find an equation that relates the variables whose rates of change were identified in Step 2. To do this, it will often be helpful to draw an appropriately labeled figure that illustrates the relationship.

4. Differentiate both sides of the equation obtained in Step 3 with respect to time to produce a relationship between the known rates of change and the unknown rate of change.

5. After completing Step 4, substitute all known values for the rates of change and the variables, and then solve for the unknown rate of change.Local Linear Approximation formulaf(x) ≈ f(x₀) + f'(x₀)(x - x₀)
f(x₀ + ∆x) ≈ f(x₀) + f'(x₀)∆x when ∆x = x - x₀Local Linear Approximation from the Differential Point of View∆y ≈ f'(x)dx = dyError Propagation Variablesx₀ is the exact value of the quantity being measured
y₀ = f(x₀) is the exact value of the quantity being computed
x is the measured value of x₀
y = f(x) is the computed value of yL'Hopital's RuleApplying L'Hopital's Rule1. Check that the limit of f(x)/g(x) is an indeterminate form of type 0/0.
2. Differentiate f and g separately.
3. Find the limit of f'(x)/g'(x). If the limit is finite, +∞, or -∞, then it is equal to the limit of f(x)/g(x).

5 0

3 years ago