Answer: the average distance between the parabola is 2000
Step-by-step explanation:
Given that;
y = 30x(20 - x) and the x-axis on the interval [0, 20]
f(x) = y = 30x(20 - x); [0, 20] and a=0, b=20
the average distance between the parabola will be
Average value = 1/20-0 ²⁰∫₀ 30x(20-x) dx
= 1/20 ²⁰∫₀ (600x-30x²) dx
= 1/20 [(600x)/2 - (30x³)/3]₀²⁰
= 1/20 [300x - 10x³]₀²⁰
inputting the limits, we get
= 1/20 [(300 × 20 × 20 - 10 × 20 × 20 × 20) - 0 - 0]
= 1/20 ( 120000 - 80000)
= 0.05 × 40000
<h2>= 2000</h2>
Therefore the average distance between the parabola is 2000
<h3 />
Differentiat each
dy/dx 5x-6=5
dy/dx x^2-2=2x
dy/dx 4x=4
domain will be all real numbers because the derivitives won't make any wierd values like divisiono by 0 or square roots of negatives
so ya, it is the last one
Hi there, -5*10/9*8=-50/72, -50/72 simplified is -25/36. Therefore, the answer is A. -25/36
Answer: r= 1.22
Step-by-step explanation:
Formula for amount with simple interest = 
, where
P= principal value , r= rate of interest , t = time.
Given: P= $2000, t= 5 years, r= 1.25% = 0.0125
Formula to compute compound amount : 
When both have same worth then
taking log on both sides , we get
Hence, Value of r= 1.22
Answer:
7/8
Step-by-step explanation:
