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Anna71 [15]
3 years ago
14

Sarah's biweekly salary is $1540 what is her of gross monthly salary

Mathematics
1 answer:
QveST [7]3 years ago
6 0
Sarah’s monthly salary would be $3,080.
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Answer:

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Step-by-step explanation:

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Tinas rent will increase from $595 this year to $708 next year what is the percent change to the nearest percent
snow_lady [41]

Answer:

The answer rounded to the nearest percent is 19%.

Step-by-step explanation:

The formula for percent change is this:

((y2 - y1) / y1)*100

Let y1 be the first value (595) and let y2 be the second (708).

((702 - 595) / 595)*100

702 - 595 is 107 and 107/595 is approximately 0.188, multiplied by 100 is 18.8, which is rounded to 19%.

That is our solution.

<em>And that's an awfully small amount of rent to pay (at least in California).</em>

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3 years ago
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The expression 17n+11 represents the perimeter of the triangle.
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3 years ago
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Consider all 5 letter "words" made from the full English alphabet. (a) How many of these words are there total? (b) How many of
VARVARA [1.3K]

Answer:

a) There are 11,881,336 of these words in total.

b) There are 7,893,600 of these words with no repeated letters.

c) 896,376 of these words start with an a or end with a z or both

Step-by-step explanation:

Our words have the following format:

L1 - L2 - L3 - L4 - L5

In which L1 is the first letter, L2 the second letter, etc...

There are 26 letters in the English alphabet.

(a) How many of these words are there total?

Each of L1, L2, L3, L4 and L5 have 26 possible options.

So there are 26^{5} = 11,881,336 of these words total

(b) How many of these words contain no repeated letters?

The first letter can be any of them, so L1 = 26.

At the second letter, the first one cannot be repeated, so L2 = L1 - 1 = 25.

At the third letter, nor the first nor the second one can be repeated, so L3 = L1 - 2 = 24

This logic applies until L5

So we have

26-25-24-23-22

In total there are

26*25*24*23*22 = 7,893,600

of these words with no repeated letters.

(c) How many of these words start with an a or end with a z or both (repeated letters are allowed)?

T = T_{1} + T_{2} + T_{3}

T_{1} is the number of words that start with an a and do not end with z. So we have

1 - 26 - 26 - 26 - 25

The first letter can only be a, and the last one cannot be z. So:

T_{1} = 26^{3}*25 = 439,400

T_{2} is the number of words that start with any letter other than a and end with z. So we have

25 - 26 - 26 - 25 - 1

The first letter can be any of them, other than a, and the last can only be z. So:

T_{2} = 26^{3}*25 = 439,400

T_{3} is the number of words that both start with a and end with z. So:

1 - 26 - 26 - 26 - 1

The first letter can only be a, and the last can only be z. The other three letters could be anything. So:

T_{3} = 26^{3} = 17,576

T = T_{1} + T_{2} + T_{3} = 2*439,400 + 17,576 = 896,376

896,376 of these words start with an a or end with a z or both

4 0
3 years ago
EXTRA POINTS!!! Write a system of three inequalities that has (2, 1) in the solution set.
Alex17521 [72]
Your system could be anything, just remember that input should be half than the output.

So, y ≥ 1/2x
5y ≥ 5/2x
10y ≥ 5x

Hope this helps!
5 0
3 years ago
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