9514 1404 393
Answer:
-11
Step-by-step explanation:
DeYanna's cards are ...
black: 2, 4, for a total value of 2+4 = 6
red: 7, 10, for a total value of -(7+10) = -17
Then the total value of DeYanna's cards is ...
6-17 = -11
Complete the equation of the line through (-10,-7)(−10,−7)(, minus, 10, comma, minus, 7, )and (-5,-9)(−5,−9)(, minus, 5, comma,
Tanzania [10]
Answer:

Step-by-step explanation:
First, the slope is determined by using the following expression:



The y-intercept is found by using the line equation, the slope and one point:




The equation of the line is:

Joe completes an average of (10 ft)/(5 h) = 2 ft/hour. Bill completes an average of (10 ft)/(4 h) = 2.5 ft/hour. Together, they complete 2+2.5 = 4.5 ft/hour. At that rate, it will take them
... (120 ft)/(4.5 ft/h) = 26 2/3 h
Answer:
We conclude that the rule for the table in terms of x and y is:
Step-by-step explanation:
The table indicates that there is constant change in the x and y values, meaning the table represents the linear function the graph of which would be a straight line.
We know the slope-intercept form of the line equation
y = mx+b
where m is the slope and b is the y-intercept.
Taking two points
Finding the slope between (-2, -4) and (-1, -1)




We know that the y-intercept can be determined by setting x = 0 and finding the corresponding y-value.
Taking another point (0, 2) from the table.
It means at x = 0, y = 2.
Thus, the y-intercept b = 2
Using the slope-intercept form of the linear line function
y = mx+b
substituting m = 3 and b = 2
y = 3x+2
Therefore, we conclude that the rule for the table in terms of x and y is:
Answer:
c) 0.932
99% confidence interval for average weights of all packages sold in small meat trays.
(0.932 ,1.071)
Step-by-step explanation:
Explanation:-
Given random sample of 35 packages in small meat trays produced weight with an average of 1.01 lbs. and standard deviation of 0.18 lbs.
size of the sample 'n' = 35
mean of the sample x⁻= 1.01lbs
standard deviation of the sample 'S' = 0.18lbs
<u>The 99% confidence intervals are given by</u>

The degrees of freedom γ=n-1 =35-1=34
tₐ = 2.0322
99% confidence interval for average weights of all packages sold in small meat trays

( 1.01 - 0.06183 , 1.01+0.06183)
(0.932 ,1.071)
<u>Final answer</u>:-
<u>99% confidence interval for average weights of all packages sold in small meat trays.</u>
<u>(0.932 ,1.071)</u>