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ELEN [110]
3 years ago
13

This one and thats it.

Mathematics
1 answer:
4vir4ik [10]3 years ago
7 0

Answer:

you just take the data given and put it on the graph

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In the table adam recorded the miles he travled each day while traveling from Florida to California. Calculate the average rate
blagie [28]

Hi!

<em>To calculate the rate of change between days 4 and 6, we simply take those points, (4, 1503) and (6, 2196) and use the equation in the picture below:</em>

<em />

Now, when we plug it in the equation, it looks like this:

\frac{2196-1503}{6-4} = \frac{693}{2} = 346.5

Therefore, your answer is 346.5 or, rounded, 347.

<em><u>Meaning, your answer is C</u></em>

<em><u></u></em>

Hope this helps and have a great day! :D

5 0
2 years ago
I dont get this please help i will mark the best
Mumz [18]

/Answer:

the verry last one

Step-by-step explanation:

3 0
3 years ago
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PLEASE HELP ME ASAP..................................
kow [346]

Answer:

2, 4, 5

Step-by-step explanation:

3 0
3 years ago
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My brother wants to estimate the proportion of Canadians who own their house.What sample size should be obtained if he wants the
AVprozaik [17]

Answer:

a) n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07

And rounded up we have that n=1476

b) n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681

And rounded up we have that n=1681

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}} (a)  

If solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2} (b)  

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by \alpha=1-0.9=0.1 and \alpha/2 =0.05. And the critical value would be given by:  

z_{\alpha/2}=\pm 1.64  

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.02 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07

And rounded up we have that n=1476

Part b

For this case since we don't have a prior estimate we can use \hat p =0.5

n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681

And rounded up we have that n=1681

8 0
3 years ago
What does the shaded part represent in the given Venn -diagram​
Snezhnost [94]
Pls look at your question before asking a question. You didn’t give us a venn diagram to look at.

Brainliest?
5 0
2 years ago
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