Cos (theta) = square of 2 / 2, and 3pi/2 < theta < 2pi, evaluate sin (theta) and tan (theta)

1 answer:

7 0

Answer: negative square root of two over 2 and tan theta is -1

Step-by-step explanation:

Did it on edge and got it right

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Cos (theta) = square of 2 / 2, and 3*pi/2 < theta < 2*pi, evaluate sin (theta) and tan (theta)