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3 years ago

Find the degree measure of each angle in the triangle.

Mathematics

1 answer:

Alex777 [14]3 years ago

4 0

Answer:

∠R = 56°
∠Q = 90°
∠S = 34°

Step-by-step explanation:

The given triangle is a right angled triangle.

So, the angles in the triangle are :

90°
(2x + 38)°
(5x - 11)°

Solving according to angle sum property,

Sum of all angles in a triangle is 180°

$\longrightarrow$ 90° + (2x + 38)° + (5x - 11)° = 180°

$\longrightarrow$ 117° + 7x = 180°

$\longrightarrow$ 7x = 180° - 117°

$\longrightarrow$ 7x = 63°

$\longrightarrow$ x = 9

Angles =

$\longrightarrow$ 2(9) + 38

$\longrightarrow$ 56°

$\longrightarrow$ 5(9) - 11

$\longrightarrow$ 34°

∠R = 56°
∠Q = 90°
∠S = 34°

The angles are 56°, 90° and 34°.

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Simplify 3 - b (7b + 2) + 3b - (11 - b)

nirvana33 [79]

Answer: -7b² + 2b - 8

Step-by-step explanation:

Given expression

3 - b (7b + 2) + 3b - (11 - b)

Expand parentheses and apply the distributive property if necessary

=3 - b · 7b - b · 2 + 3b - 11 + b

=3 - 7b² - 2b + 3b - 11 + b

Combine like terms

=-7b² + (3b - 2b + b) + (3 - 11)

= $\boxed{-7b^2+2b-8}$

Hope this helps!! :)

Please let me know if you have any questions

8 0

3 years ago

What are three ratios equvilent to 8:20

Genrish500 [490]

Answer:

see explanation

Step-by-step explanation:

Multiplying or dividing each part of the ratio gives an equivalent ratio

Given

8 : 20 ← divide both parts by 2

= 4 : 10 ← divide both parts by 2

= 2 : 5 ← ratio in simplest form

Multiply both parts by 2

8 : 20 = 16 : 40

4 : 10, 2 : 5, 16: 40 ← are possible equivalent ratios

3 0

3 years ago

A rocket is launched into the air. The projectile motion of the rocket can be modeled using h(t) = 112t –16t2, where t is the ti

asambeis [7]

Answer:

3.5 seconds.

Step-by-step explanation:

because i just took the test.

5 0

2 years ago

Please answer correctly !!!!!!!!!!!!!!!!!!!!! Will mark brainliest !!!!!!!!!!!!!!!!!!!

Over [174]

Answer:

n = 11

General Formulas and Concepts:

Order of Operations: BPEMDAS
Equality Properties
Vertical Angles: Angles that are across from each other and are congruent

Step-by-step explanation:

Step 1: Set up equation

Vertical angles must be congruent.

(6n - 4)° = (5n + 7)°

Step 2: Solve for n

Subtract 5n on both sides: n - 4 = 7
Add 4 to both sides: n = 11

8 0

3 years ago

If triangle ABC is similar to triangle DEC, find the values of x and y.

Mumz [18]

The values are x=8 and y=35, if the given ΔABC and ΔDEC are equal, it is obtained by Pythagoras theorem.

Step-by-step explanation:

The given are,

From ΔABC,

AB= 6

BC= 10

AC = x

From ΔDEC,

CD= 28

DE= 21

CE = y

Step:1

Pythagoras theorem from ΔABC,

$BC^{2}=AB^{2} + AC^{2}$ ...............(1)

Substitute the values,

$10^{2}$ = $6^{2}$ + $AC^{2}$

100 = 36 + $AC^{2}$

$AC^{2}$ = 100 - 36

= 64

AC = $\sqrt{64}$

AC = 8

AC = x = 8

Step:2

Pythagoras theorem for ΔDEC,

$CE^{2} = CD^{2} + DE^{2}$ ................(2)

From the values,

$CE^{2}$ = $28^{2}$ + $21^{2}$

$CE^{2}$ = 784 + 441

= 1225

CE = $\sqrt{1225}$

CE = 35

CE = y = 35

Result:

The values are x=8 and y=35, if the given ΔABC and ΔDEC are equal.

5 0

3 years ago