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Lera25 [3.4K]
4 years ago
6

Solve for x: 3|x − 3| 2 = 14

Mathematics
1 answer:
bixtya [17]4 years ago
3 0
Go to a website called Mathpapa. It is an algebra calculator and it solves it for you
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Consider the formula d = , where
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kg/ m³

Step-by-step explanation:

Since density is= \frac{mass}{volume}, where mass is in kg and volume is in cm³, the unit of density would follow so it is kg/m³.

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In 2010, the number of clown costumes sold at a single costume shop was 10. By 2015, that number had grown to 40. Assuming a con
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I would say the average sale is 15.

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Select all ratios equivalent to 10:2.
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5:1

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11/9 converted to a mixed number is
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To write an improper fraction as a mixed number, divide the denominator into the numerator.

Image is provided.

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3 years ago
The function f(x) = (x − 4)(x − 2) is shown. what is the range of the function?
defon

Answer:

y\geq -1

All real numbers greater than or equal to -1

Step-by-step explanation:

we know that

The equation of a vertical parabola in vertex form is equal to

f(x)=a(x-h)^{2}+k

where

(h,k) is the vertex of the parabola

if a> 0 ----> the parabola open upward ( vertex is a minimum)

if a< 0 ----> the parabola open downward ( vertex is a maximum)

In this problem we have

f(x)=(x-4)(x-2)

Convert to vertex form

f(x)=(x-4)(x-2)=x^{2} -2x-4x+8\\f(x)=x^{2}-6x+8

Group terms that contain the same variable, and move the constant to the opposite side of the equation

f(x)-8=x^{2}-6x

Complete the square. Remember to balance the equation by adding the same constants to each side.

f(x)-8+9=x^{2}-6x+9

f(x)+1=x^{2}-6x+9

Rewrite as perfect squares

f(x)+1=(x-3)^{2}

f(x)=(x-3)^{2}-1 -------> equation in vertex form

The vertex is the point (3,-1)

a=1

therefore

a> 0 ----> the parabola open upward ( vertex is a minimum)

The range of the function is the interval-------> [-1,∞)

y\geq -1

All real numbers greater than or equal to -1

see the attached figure to better understand the problem

8 0
4 years ago
Read 2 more answers
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