I believe the term you are looking for would be "genotype".
Genotype is the combination of the offspring alleles (or, the alleles inherited from the parents).
Hope this helped you! :)
The right answer is 57 (%)
The Bohr effect is the decrease of the oxygen attached to the hemoglobin when the pH decreases or when the CO2 level increases.
at the level of the lungs, one tends to find slightly alkaline pH due to the reduced CO2 pressure compared to the blood level, therefore the affinity of the oxygen with the hemoglobin is high and corresponds to the green curve. or the saturation of oxygen is 100% to 100mmHg of oxygen.
At the tissue level, there is more CO2 (waste) and less O2 (since it is consumed) and the pH is more acidic than that of blood pH (due to CO2 and the decrease of bicarbonate at this level) . This causes a deviation of the curve to the right as shown in the diagram with the red color curve. A saturation coefficient of 43% at 30 mmHg of the oxygen can be observed.
When subtracting between the two values: 100 - 43 = 57%
Answer:
Helicase. It unwinds and breaks the hydrogen bonds so other molecules can move on to the DNA strand and begin replication
Explanation:
P I and PII are proteic compounds present in the thylakoid membrane that contain about 300 chlorophyll molecules each.
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<u>Step I</u></em></h2>
First of all light with a wavelength of 690nm is absorbed by P II. The light excites an electron that leads to the photolysis of water(H2O--->2H+ +2e- + 1/2O2). The two electrons released go into the electron transport chain. The second compound in electron transport chain is plastoquinone that is reduced when it accepts electrons then oxidised when it loses them to P I. The next two compounds are cytocromes that make hydrogen protons go inside the thylakoid when they recieve the electrons.(I will mention what happens to the H+ in the second step). The next compound in the electron transport chain is a compound that contains Fe and S. The electrons finally reach the last step: Reduction of NADP+ to NADPH+H+.
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Step II</u></em></h2>
In the second step is ATP synthesis. Hydrogen protons accumulate inside the thylakoid membrane. An electrochemical gradient is formed. The protons can leave the thylakoid according to this gradient through an enzyme.
When the protons flow through , it turns ADP into ATP.
<u>To sumarize: the role of P II is O2 production through photolysis and ATP synthesis(indirectly) The role of P I is NADPH+H+ synthesis.</u>
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