Answer:
A. Z = 2 + N13
Step-by-step explanation:
Let's solve your equation step-by-step.
0=z2+4z−9
Step 1: Subtract z^2+4z-9 from both sides.
0−(z2+4z−9)=z2+4z−9−(z2+4z−9)
−z2−4z+9=0
For this equation: a=-1, b=-4, c=9
−1z2+−4z+9=0
Step 2: Use quadratic formula with a=-1, b=-4, c=9.
z=
−b±√b2−4ac
2a
z=
−(−4)±√(−4)2−4(−1)(9)
2(−1)
z=
4±√52
−2
z=−2−√13 or z=−2+√13
Spencer would be the correct one because it's easier to keep your variables positive when trying to solve. Therefore, in order to keep the variable positive, one would have to add 4x to both sides.
Answer:
SA: 38
Step-by-step explanation:
3 + 12 + 3 + 4 + 16 =
15 + 7 + 16 =
22 + 16 =
38
Answer:
Taking P(x) = x³-12x-16 as an example
Step-by-step explanation:
For a polynomial, if
x = a is a zero of the function, then (x − a) is a factor of the function.
We have two unique zeros:
−2 and 4. However, −2 has a multiplicity of 2, which means that the factor that correlates to a zero of −2 is represented in the polynomial twice.
Following how it's constructed
zero at -2, multiplicity 2
zero at 4, multiplicity 1
p(x)=x−(−2))²(x−4)¹
Thus,p(x)=(x+2)²(x−4)
Expand: p(x)=(x²+4x+4)(x−4)
p(x) =x³−12x−16
