Some diseases (such as typhoid fever) are spread largely by carriers, individuals who can transmit the disease but who exhibit n
o overt symptoms. Let x and y denote the proportions of susceptibles and carriers, respectively, in the population. Suppose that carriers are identified and removed from the population at a rate β, so dy/dt = −βy. Suppose also that the disease spreads at a rate proportional to the product of x and y; thus dx/dt = −αxy. a) Determine y at tany time t by solving eq(i) subject to the initial condition y(0)=y0
b) Use the result of part (a) to find x at any time t by solving Eq.(ii) subject to the initial condition x(0)=x0
c) Find the proportion of the population that escapes the epidemic by finding the limiting value of x as t approaches infinity
b) Use the result of part (a) to find x at any time t by solving Eq.(ii) subject to the initial condition x(0)=x0
c) Find the proportion of the population that escapes the epidemic by finding the limiting value of x as t approaches infinity
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Given :7x+6=5(x+2)
Now We will use the distributive property to multiply 5 by x+2.
→7x+6=5x+10
We will Subtract 5x from both sides.
→7x+6−5x=10
We will Combine 7x and −5x to get 2x.
→2x+6=10
We will Subtract 6 from both sides.
2x=10−6
We will Subtract 6 from 10 to get 4.
2x=4
We will Divide both sides by 2.
x= 4/2
At last,We Divide 4 by 2 to get 2.
x=2
