Some diseases (such as typhoid fever) are spread largely by carriers, individuals who can transmit the disease but who exhibit n
o overt symptoms. Let x and y denote the proportions of susceptibles and carriers, respectively, in the population. Suppose that carriers are identified and removed from the population at a rate β, so dy/dt = −βy. Suppose also that the disease spreads at a rate proportional to the product of x and y; thus dx/dt = −αxy. a) Determine y at tany time t by solving eq(i) subject to the initial condition y(0)=y0
b) Use the result of part (a) to find x at any time t by solving Eq.(ii) subject to the initial condition x(0)=x0
c) Find the proportion of the population that escapes the epidemic by finding the limiting value of x as t approaches infinity
b) Use the result of part (a) to find x at any time t by solving Eq.(ii) subject to the initial condition x(0)=x0
c) Find the proportion of the population that escapes the epidemic by finding the limiting value of x as t approaches infinity
1 answer:
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Answer:
Okapi 290 kg
Llama 160 kg
Step-by-step explanation:
Let weight of each llama be
Let weight of each okapi be
<em>Given, combined weight of 1 okapi and 1 llama is 450, we can write:</em>
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<em>Also, average weight of 3 llama is 190 more than the average weight of 1 okapi, thus we can write:</em>
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Now, substituting 2nd equation into 1st equation, we can solve for weight of 1 llama:
Each llama weights 160 kg, now using this and plugging into 2nd equation, we get weight of 1 okapi to be:
Each okapi weigh 290 kg