Some diseases (such as typhoid fever) are spread largely by carriers, individuals who can transmit the disease but who exhibit n
o overt symptoms. Let x and y denote the proportions of susceptibles and carriers, respectively, in the population. Suppose that carriers are identified and removed from the population at a rate β, so dy/dt = −βy. Suppose also that the disease spreads at a rate proportional to the product of x and y; thus dx/dt = −αxy. a) Determine y at tany time t by solving eq(i) subject to the initial condition y(0)=y0
b) Use the result of part (a) to find x at any time t by solving Eq.(ii) subject to the initial condition x(0)=x0
c) Find the proportion of the population that escapes the epidemic by finding the limiting value of x as t approaches infinity
b) Use the result of part (a) to find x at any time t by solving Eq.(ii) subject to the initial condition x(0)=x0
c) Find the proportion of the population that escapes the epidemic by finding the limiting value of x as t approaches infinity
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Actually Welcome to the Concept of the volumes.
Here given as, r= 6.2 mm, h = 10.8 mm, π=3.14
hence, the volume of the cone is
Volume = 1/3(πr^2h)
===> vol = 1/3(3.14*(6.2)^2*(10.8))
==> Vol = 1/3*(1303.57)
==> Vol = 434.52 mm^3
Hence the volume of the cone is 434.52 mm^3