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kirza4 [7]
4 years ago
14

Some diseases (such as typhoid fever) are spread largely by carriers, individuals who can transmit the disease but who exhibit n

o overt symptoms. Let x and y denote the proportions of susceptibles and carriers, respectively, in the population. Suppose that carriers are identified and removed from the population at a rate β, so dy/dt = −βy. Suppose also that the disease spreads at a rate proportional to the product of x and y; thus dx/dt = −αxy. a) Determine y at tany time t by solving eq(i) subject to the initial condition y(0)=y0
b) Use the result of part (a) to find x at any time t by solving Eq.(ii) subject to the initial condition x(0)=x0
c) Find the proportion of the population that escapes the epidemic by finding the limiting value of x as t approaches infinity

Mathematics
1 answer:
Margaret [11]4 years ago
6 0

Answer:

The detailed derivation is shown in the attachment

Step-by-step explanation:

The step by step explanation is as shown in the attachment.

Basically, what was applied is the knowledge of differentiation and integration.

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Phonesmart is having a sale on Bananas. If you buy one Banana at full price, you get a second at half price. When couples come i
Mice21 [21]

Answer:

<u>The probability that a couple buys a pair of Bananas is 1/3 or 33.3%</u>

Step-by-step explanation:

Let's recall that the formula of probability is:

Probability = Number of favorable outcomes/Total number of possible outcomes

What is the probability that a couple buys a pair of Bananas?

For answering this question, we first need to calculate the probability of buying a first Banana, given that when couples come in to buy a pair of phones, sales of Apricots and Bananas are equally likely:

Probability of buying a first Banana = 1/2

Probability of buying a first Apricot = 1/2

Now, we can calculate the probability of buying a second Banana, given that the second phone is twice as likely to be a Banana rather than an Apricot.

Probability of buying a second phone = 1

Probability of buying a second Apricot = x

Probability of buying a second Banana = 2x

Solving for x, we have:

x + 2x = 1

3x = 1

x = 1/3 ⇒ 2x = 2/3

Thus, probability of buying a second Banana = 2/3

Finally,

Probability that a couple buys a pair of Bananas = Probability of buying a first Banana * Probability of buying a second Banana

Replacing with the values we know:

Probability that a couple buys a pair of Bananas = 1/2 * 2/3 = 2/6 = 1/3

1/3 = 33.3%

<u>Probability that a couple buys a pair of Bananas = 1/3 or 33.3%</u>

6 0
3 years ago
How would you describe the difference
zimovet [89]
I think the answer would be A. But double check with the graph I posted.

5 0
3 years ago
Can someone help me please​
riadik2000 [5.3K]

Answer:

50 People

Step-by-step explanation:

The answer must be 50 people because if you add up all the data it shows

6 0
3 years ago
Which values are solutions to the inequality below? Check all that apply.
Tamiku [17]

Answer:

b,d

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Please work out Y, please give workings. For 80 pointssss!!
evablogger [386]
I can help you out, 8+10 x Square root of 2 is 22.1421356237 and then you simply take that and multiply it by 90* and y by 30* and i believe you have to use the Sin function on a calculator so

Sin90 X Sin 30
22.14 X      Y

Cross multiply
7 0
3 years ago
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