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blondinia [14]
3 years ago
7

Please help me IDk this at all!!!!

Mathematics
2 answers:
nekit [7.7K]3 years ago
5 0
You do have enough because 1/3 + 1/3 = 2/3 and 2/3 < 3/4.

jasenka [17]3 years ago
3 0
It would help if you find common denominator... 12
so 1/3 times 4 both the numerator and denominator
4/12

and 3/4 times by 3 both the numerator and denominator
9/12

the recipe calls for 4/12 cup of oil and you have 9/12

two batches would be 8/12 cups of oil, you have 9/12 that is just enough for the recipe for two batches...

now to simplify it again, 1/3 + 1/3 = 2/3 and 2/3 is less than 3/4 
the answer would be the upper right
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What is true about the complex number: -5-5i? check all that apply.
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It is c and d. If this helps you are welcome

Step-by-step explanation:

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3 years ago
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<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%20%5Csqrt%7Bx%20%5Csqrt%7Bx%20%5Csqrt%7Bx....%7D%20%7D%20%7D%20%7D%20%20%3D%20%
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First observe that if a+b>0,

(a + b)^2 = a^2 + 2ab + b^2 \\\\ \implies a + b = \sqrt{a^2 + 2ab + b^2} = \sqrt{a^2 + ab + b(a + b)} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b(a+b)}} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b(a+b)}}} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{\cdots}}}}

Let a=0 and b=x. It follows that

a+b = x = \sqrt{x \sqrt{x \sqrt{x \sqrt{\cdots}}}}

Now let b=1, so a^2+a=4x. Solving for a,

a^2 + a - 4x = 0 \implies a = \dfrac{-1 + \sqrt{1+16x}}2

which means

a+b = \dfrac{1 + \sqrt{1+16x}}2 = \sqrt{4x + \sqrt{4x + \sqrt{4x + \sqrt{\cdots}}}}

Now solve for x.

x = \dfrac{1 + \sqrt{1 + 16x}}2 \\\\ 2x = 1 + \sqrt{1 + 16x} \\\\ 2x - 1 = \sqrt{1 + 16x} \\\\ (2x-1)^2 = \left(\sqrt{1 + 16x}\right)^2

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(we omit x=0 since 2\cdot0-1=-1\ge0 is not true)

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