<u>Answer:</u>
42%
<u>Step-by-step explanation:</u>
We know that the number of times red side is faced up = 21; and
the total number of times colored chip is thrown = 50
Frequency of red side = (No of times red side is faced up / Total number of times colored chip is thrown) * 100%
Frequency of red side = (21 / 50) * 100% = 0.42 * 100 = 42%
Therefore, the relative frequency of the chip landing with the red side facing up is 42%.
Answer:
one solution, (-1,0)
Step-by-step explanation:
Answer: 
Step-by-step explanation:
Given: Sample size: n = 41
Sample mean 
degrees
Population standard deviation 
degrees
Confidence level (c) = 80% =0.80
Significance level (a) = 1- c = 1-0.80 = 0.20
z-score for 80% confidence level : z = 1.2816 [from z-table]
Confidence level for population mean :-
Hence, 80% confidence interval for the temperatures in the freezer
Answer:
Original position: base is 1.5 meters away from the wall and the vertical distance from the top end to the ground let it be y and length of the ladder be L.
Step-by-step explanation:
By pythagorean theorem, L^2=y^2+(1.5)^2=y^2+2.25 Eq1.
Final position: base is 2 meters away, and the vertical distance from top end to the ground is y - 0.25 because it falls down the wall 0.25 meters and length of the ladder is also L.
By pythagorean theorem, L^2=(y -0.25)^2+(2)^2=y^2–0.5y+ 0.0625+4=y^2–0.5y+4.0625 Eq 2.
Equating both Eq 1 and Eq 2: y^2+2.25=y^2–0.5y+4.0625
y^2-y^2+0.5y+2.25–4.0625=0
0.5y- 1.8125=0
0.5y=1.8125
y=1.8125/0.5= 3.625
Using Eq 1: L^2=(3.625)^2+2.25=15.390625, L=(15.390625)^1/2= 3.92 meters length of ladder
Using Eq 2: L^2=(3.625)^2–0.5(3.625)+4.0625
L^2=13.140625–0.90625+4.0615=15.390625
L= (15.390625)^1/2= 3.92 meters length of ladder
<em>hope it helps...</em>
<em>correct me if I'm wrong...</em>
