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qaws [65]
2 years ago
7

Need help with this math lesson

Mathematics
1 answer:
never [62]2 years ago
8 0

Answer: 50.24

3.14 x 4²

3.14 x 16

50.24

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In which year will 67% of babies be born out of wedlock?
Leviafan [203]

Based on the trend of the increase in children born out of wedlock, if this trend keeps increasing, the year with 67% of babies born out of wedlock will be 2055 .

<h3>What year will 67% of babies be born to unmarried parents?</h3><h3 />

In 1990, the 28% of children were born out of wedlock and this trend was increasing by 0.6% per year.

If the trend continues, the number of years till 67% of children born out of wedlock will be:

= (67%  - 28%) / 0.6%

= 65 years

The year will be:

= 1990 + 65

= 2055

The first part of the question is:

According to the National Center for Health Statistics, in 1990, 28% of babies in the United States were born to parents who were not married. Throughout the 1990s, this percentage increased by approximately 0.6 per year.

Find out more on benefits of marriage at brainly.com/question/12132551.

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What is the area of the following shape? Do not put units.
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Answer:

Area = 30

Step-by-step explanation:

Add the two sides

8 + 4 = 12

Multiply that number by the height

12 × 5 = 60

Divide that number by 2

60 ÷ 2 = 30

4 0
2 years ago
Which steps could be used to solve this story problem? Krissy had 32 bagels. She gave an equal number of bagels to each child. T
Elina [12.6K]
D, because it said that Krissy had equally distributed the bagels to each child, so 32/8=4, and then it asked how many bagels did the girls get all together, so it's 4x3=12
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2 years ago
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Question : In the given figure , ∆ APB and ∆ AQC are equilateral triangles. Prove that PC = BQ.
lorasvet [3.4K]

Answer:

See Below.

Step-by-step explanation:

We are given that ΔAPB and ΔAQC are equilateral triangles.

And we want to prove that PC = BQ.

Since ΔAPB and ΔAQC are equilateral triangles, this means that:

PA\cong AB\cong BP\text{ and } QA\cong AC\cong CQ

Likewise:

\angle P\cong \angle PAB\cong \angle ABP\cong Q\cong \angle QAC\cong\angle ACQ

Since they all measure 60°.

Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:

m\angle PAC=m\angle PAB+m\angle BAC

Likewise:

m\angle QAB=m\angle QAC+m\angle BAC

Since ∠QAC ≅ ∠PAB:

m\angle PAC=m\angle QAC+m\angle BAC

And by substitution:

m\angle PAC=m\angle QAB

Thus:

\angle PAC\cong \angle QAB

Then by SAS Congruence:

\Delta PAC\cong \Delta BAQ

And by CPCTC:

PC\cong BQ

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2 years ago
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Which of the following is a specific species designation
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Sapien because the word homo in homo sapien is the genus name, while the word sapien is the species name.

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