6k+(3•10-8)=(3•3)k+22

In this problem, we explore the effect on the standard deviation of adding the same constant to each data value in a data set. c

goldenfox [79]

The standard deviation of both the data are the same which is 3.67 and adding the same constant c to each data value results in the standard deviation remaining the same.

<h3>What is the standard deviation?</h3>

It is defined as the measure of data disbursement, It gives an idea about how much is the data spread out.

We have a data set:

8, 16, 14, 8, 16

As we know the formula for standard deviation is:

$\rm \sigma = \sqrt{\dfrac{ \sum (x_i-X)}{n}$

Here σ is the standard deviation

xi is each value from the data set

X is the mean of the data set

n is the number of observation in data set.

X = (8+16+14+8+16)/5 = 12.4

n = 5

After calculating the standard deviation will be:

σ = 3.67

Add 8 to each data value to get the new data set 16, 24, 22, 16, 24.

New standard deviation:

σ(new) = 3.67

The standard deviation of both the data are same we can say the standard deviation does not change when we add a constant to each data value.

Adding the same constant c to each data value results in the standard deviation remaining the same.

Thus, the standard deviation of both the data are the same which is 3.67 and adding the same constant c to each data value results in the standard deviation remaining the same.

Learn more about the standard deviation here:

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6 0

2 years ago

MN0 with vertices M(4,-5), N(5,-8), O(8, -6) ; translate the new figure M'N'O' (-2,5)

Aleks04 [339]

If you are translating a graph (-2,5), the easiest way to find the new points is to subtract the x value of each coordinate (M, N, and O) by 2. This will give you the new x values for the translated coordinates. Then, to find the new y values, add 5 to the y values of each coordinate. Then put the new x value and new y value in the form of a coordinate, and that will be your answer.

5 0

3 years ago

Combine any like terms in the expression. If there are no like terms, rewrite the expression.

stich3 [128]

Answer:

40w^3

Step-by-step explanation:

I'm assuming you meant w^3 (w to the third power). In that case, you would just add 34 + 13 + 11 - 18 because they are all like terms (coefficients of w^3).

5 0

2 years ago

La banqueta que rodea un jardín rectangular es de 4 metros de ancho. El jardín tiene

mylen [45]

Answer:

jbhbchbhvbbhcbrhfbcbhshshbhsvhbhv;b;rvbhbhcrbihcbhc

Step-by-step explanation:

3 0

3 years ago

WILL GIVE BRAINLIEST!

Zielflug [23.3K]

Answer:

Collisions

Follow Newton’s Third Law which tells us that

the force exerted by body A on body B in a

collision is equal and opposite to the force

exerted on body B by body A.

During a collision, external forces are ignored.

The time frame of the collision is very short.

The forces are impulsive forces (high force, short

duration).

Collision Types

Elastic: P is conserved, K is conserved

Inelastic: P is conserved, K is NOT conserved

Perfectly Inelastic means the bodies stick together

Problem: Collisions (1993)

10. Which of the following is true when an object of

mass m moving on a horizontal frictionless surface

hits and sticks to an object of mass M > m, which is

initially at rest on the surface?

(A) The collision is elastic.

(B) All of the initial kinetic energy of the less-massive

object is lost.

(C) The momentum of the objects that are stuck together

has a smaller magnitude than the initial momentum of

the less-massive object.

(D) The speed of the objects that are stuck together

will be less than the initial speed of the less-massive

object.

(E) The direction of motion of the objects that are stuck

together depends on whether the hit is a head-on

collision.

Explain your reasoning:

Ans. Again, by conservation of momentum, if the

mass increases, the velocity must decrease. pin = pout

Problem: Collisions (1993)

11. Two objects having the same mass travel

toward each other on a flat surface, each with a

speed of 10 meter per second relative to the

surface. The objects collide head-on and are

reported to rebound after the collision, each

with a speed of 20 meters per second relative

to the surface. Which of the following

assessments of this report is most accurate?

(A) Momentum was not conserved, therefore the report is false.

(B) If potential energy was released to the objects

during the collision, the report could be true.

(C) If the objects had different masses, the report could be true.

(D) If the surface was inclined, the report could be true.

(E) If there was no friction between the objects and the

surface, the report could be true.

Explain your reasoning:

Ans. Momentum is conserved provided that an

external force not be applied. If the objects have

potential energy stored, this could provide the force.

PLEASE MARK AS BRAINLIEST!!!!!!

7 0

3 years ago