Answer:
Step-by-step explanation:
Hello!
A line that is perpendicular to another has an opposite-reciprocal slope.
Meaning:
- Flip the sign (+/-)
- Flip the fraction
The slope perpendicular to 3/5 would be -5/3.
We can solve for the y-intercept by plugging in the x and y values given from the coordinate into the equation with out new slope.
<h3 /><h3>Solve for B</h3>
The y-intercept of the new line is 20.
The equation is
Answer:
12
(If needed explanation ask in the comments! ty)
Hope This Helps! •v•
A
Volume of the Cylinder
Givens
H = 60 yards.
Diameter = 20 yards
pi = 3.14
Formula
V = pi * r^2 * h
Calculations
r = d/2
r = 32/2
r = 16
V = 3.14 * 16^2 * 60
V = 48230 cubic yards [Cylinder's Volume]
Cone
<em>Formula</em>
V = 1/3 pi r^2 H
<em>Givens</em>
pi = 3.14
r = 16 yards
h = 20 yards
<em>Sub and solve</em>
V = 1/3 3.14 * 16^2 * 20
V = 5359 cubic yards.
<em>Total Volume of the structure</em>
48230 + 5359 = 53589 Cubic Yards
<em>Water Content</em>
The answer to this part requires a proportion.
1 Cubic yard will hold 201.97 gallons.
53589 yd^3 = x
1/201.97 = 53589 /x [ You should get a pretty big answer]
x = 201.87 * 53589
x = 10 819 092 gallons can be held by the tank.
10 819 092 gallons <<<< answer
B
If the height of both the cylinder and the cone remain the same. If the radius doubles in both the cylinder and the cone then the tank will hold 4 times as much.
Total volume before doubling the radius = pi * r^2 h + 1/3 pi r^2 h
New Total Volume = pi * (2*r)^2 h + 1/3 pi * (2r)^2 h
New Total volume = pi * 4r^2 h + 1/3 pi *4 r^2 h
New Total Volume = 4 [pi r^2 h + 1/3 pi r^2 h]
but pi r^2 h + 1/3 pi r^2 h is the total volume before doubling the radius
New volume = 4 original volume. <<<<< answer to part B
The surface area would be 68 squared inches. I hope this helps!
There is a line and a parabola in the graph.
So, we will get the solution set from the point of intersection of both line and parabola.
Notice that the parabola and the line intersecting at two points E(1, 5) and C(-0.5,2).
So, the solution set is E(1, 5) and C(-0.5,2).
