2 years ago

Let f(x)=8secx. Then f′′(π/9)

Mathematics

1 answer:

Ahat [919]2 years ago

7 0

f(x)=secx.

f'(x)=sec x tan x.

Use the product rule to find f ' '(x).

F ' '(x)=(secxtanx)tanx+secx(sec2x).

So, f ' '(x)=secxtan2x+sec3x.

Evaluate:f ' '(π4)=sec(π4)tan2(π4)+sec3(π4)=(√2)(1)2+(√2)3=√2+2√2=3√2.

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