(d) The particle moves in the positive direction when its velocity has a positive sign. You know the particle is at rest when 
and 
, and because the velocity function is continuous, you need only check the sign of 
for values on the intervals (0, 3) and (3, 6).
We have, for instance 
and 
, which means the particle is moving the positive direction for 
, or the interval (3, 6).
(e) The total distance traveled is obtained by integrating the absolute value of the velocity function over the given interval:
which follows from the definition of absolute value. In particular, if 
is negative, then 
.
The total distance traveled is then 4 ft.
(g) Acceleration is the rate of change of velocity, so 
is the derivative of :
Compute the acceleration at 
seconds:
(In case you need to know, for part (i), the particle is speeding up when the acceleration is positive. So this is done the same way as part (d).)
Answer:
hi buddy
Step-by-step explanation:
1 50
2 5 %
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Answer:
d
Step-by-step explanation:
The answer must have a negative slope because the graph is decreasing.
The y-intercept is 10. The equation must have +10 at the end.
y = -3x + 10
Answer:
true
Step-by-step explanation:
v = 1/3Bh
Divide both sides by h.
v/h = 1/3B
Multiply both sides by 3.
3v/h = B
