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DedPeter [7]
3 years ago
15

Equation of a line that passes through (2,4) and has a slope of 3. Point slope method

Mathematics
1 answer:
olchik [2.2K]3 years ago
3 0
Y-y1=m(x-x1)

Thru that, you get:

y-4 = 3(x-2)
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X(3 + 4 + 8) + 7 hhelp pls
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Answer:

15x + 7

Step-by-step explanation:

To solve the equation, you distribute the x to all the terms within the parentheses. When you distribute, you get:

3x + 4x + 8x + 7

Add all the like terms and you get the final answer.

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∠1 and​ ​ ∠2 ​ ​are complementary angles. m∠1=13° What is the measure of ​ ∠2 ​​?
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Measure of angle 2 is 77. hope this helped.
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3 years ago
Samples of laboratory glass are in small, light packaging or heavy, large packaging. Suppose that 2% and 1%, respectively, of th
mixer [17]

Answer:

The solution is attached below:

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A point with a positive x-coordinate and a negative y-coordinate is reflected over the y-axis.
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3 years ago
Consider the differential equation: xy′(x2+7)y=cos(x)+e3xy. Put the differential equation into the form: y′+p(x)y=g(x), determin
icang [17]

Answer:

Linear and non-homogeneous.

Step-by-step explanation:

We are given that

\frac{xy'}{(x^2+7)y}=cosx+\frac{e^{3x}}{y}

We have to convert into y'+P(x)y=g(x) and determine P(x) and g(x).

We have also find type of differential equation.

y'=\frac{(x^2+7)y}{x}(cosx+\frac{e^{3x}}{y}}

y'=\frac{(x^2+7)cosx}{x}y+\frac{(x^2+7)e^{3x}}{x}

y'-\frac{cosx(x^2+7)}{x}y=\frac{e^{3x}(x^2+7)}{x}

It is linear differential equation because  this equation is of the form

y'+P(x)y=g(x)

Compare it with first order first degree linear differential equation

y'+P(x)y=g(x)

P(x)=-\frac{cosx (x^2+7)}{x},g(x)=\frac{e^{3x}(x^2+7)}{x}

\frac{dy}{dx}=\frac{(x^2+7)(ycosx+e^{3x})}{x}

Homogeneous equation

\frac{dy}{dx}=\frac{f(x,y)}{g(x,y)}

Degree of f and g are same.

f(x,y)=(x^2+7)(ycosx+e^{3x}),g(x,y)=x

Degree of f and g are not same .

Therefore, it is non- homogeneous .

Linear and non-homogeneous.

3 0
3 years ago
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