The probability that a randomly selected carton has a puncture or a smashed corner is 12.6%.
In this problem, the events are:
Event A: Puncture.
Event B: Smashed corner.
The "or" probability is given by:
∩
5% have a puncture, hence 
8% have a smashed corner, hence 
0.4% have both a puncture and a smashed corner, hence
Then:

Therefore, The probability that a randomly selected carton has a puncture or a smashed corner is 12.6%.
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Assuming you're trying to find t, first you would plug in the numbers given to get 105=(700)(.05)t
next, you multiply p and r to get 105=35t
after that, you divide the 105 by 35 to get the final answer of t=3
Answer:
k= 112
Step-by-step explanation:
12y = 7z
y= 7z/12
_________
3x =8y
3x= 8× 7z/12
3×=56z/12
36x=56z
x=56z/36
_________
zk=72x
zk= 72 ×(56z/36)
k= (72×56)/36
k=112
Z=1/4 that is the answer to this problem hope it helped