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Lady_Fox [76]
3 years ago
9

Consider the differential equation: xy′(x2+7)y=cos(x)+e3xy. Put the differential equation into the form: y′+p(x)y=g(x), determin

ing p(x) and g(x). p(x)= g(x)= Is the differential equation linear and homogeneous, linear and nonhomogeneous, or nonlinear?
Mathematics
1 answer:
icang [17]3 years ago
3 0

Answer:

Linear and non-homogeneous.

Step-by-step explanation:

We are given that

\frac{xy'}{(x^2+7)y}=cosx+\frac{e^{3x}}{y}

We have to convert into y'+P(x)y=g(x) and determine P(x) and g(x).

We have also find type of differential equation.

y'=\frac{(x^2+7)y}{x}(cosx+\frac{e^{3x}}{y}}

y'=\frac{(x^2+7)cosx}{x}y+\frac{(x^2+7)e^{3x}}{x}

y'-\frac{cosx(x^2+7)}{x}y=\frac{e^{3x}(x^2+7)}{x}

It is linear differential equation because  this equation is of the form

y'+P(x)y=g(x)

Compare it with first order first degree linear differential equation

y'+P(x)y=g(x)

P(x)=-\frac{cosx (x^2+7)}{x},g(x)=\frac{e^{3x}(x^2+7)}{x}

\frac{dy}{dx}=\frac{(x^2+7)(ycosx+e^{3x})}{x}

Homogeneous equation

\frac{dy}{dx}=\frac{f(x,y)}{g(x,y)}

Degree of f and g are same.

f(x,y)=(x^2+7)(ycosx+e^{3x}),g(x,y)=x

Degree of f and g are not same .

Therefore, it is non- homogeneous .

Linear and non-homogeneous.

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