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Lemur [1.5K]
2 years ago
12

Dominic is deciding if he should become a member of his local ice rink.

Mathematics
1 answer:
babymother [125]2 years ago
6 0

After 4 visits, members would pay $160

After 4 visits, non-members would pay $80

After 6 visits, members would pay $168

After 6 visits, non-members would pay $120.

The equation that can be used to solve for the number of visits the cost would be equal is $144 + 4n = $20n

The total cost for members and non-members would be $180.

Dominic can guess the number of visits he plans to make in a year. If it would be greater than 9, he should pay for the membership. If not, he should not become a member.

<h3>What is the total cost for members and non members after 4 and 6visits?</h3>

Total cost for members = annual fee + (number of visits x cost per visit)

Total cost for non-members = (admissions + parking + cost of renting the ice skate) x number of visits

After 4 visits:

Total cost for members = $144 + (4 x 4) = $160

Total cost for non-members = (11 + 5 + 4) x 4 = $80

After 6 visits:

Total cost for members = $144 + (4 x 6) = $168

Total cost for non-members = (11 + 5 + 4) x 6 = $120

The equation that can be used to solve for the number of visits the cost would be equal is: $144 + 4n = $20n

In order to determine the value of n, take the following steps:

Combine similar terms: $144 = $20n - $4n

Add similar terms together : $144 = $16n

Divide both sides by 16 : 144 / 16

n = 9

Total cost = $20 x 9 = $180

To learn more about total cost, please check: brainly.com/question/25717996

#SPJ1

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Answer:

1. 0.0000454

2. 0.01034

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4. 0.918

Step-by-step explanation:

Let X be the random variable denoting the number of passengers arriving in a minute. Since the mean arrival rate is given to be 10,  

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1. Requires us to compute

P(X = 0) = e^{-10} \frac{10^0}{0!} = 0.0000454

2.  We need to compute P(X \leq 3) = P(X =0) + P(X =1) + P(X =2) + P(X =3)

P(X =1) = e^{-10} \frac{10^1}{1!} = 0.000454

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P(X =3) = e^{-10} \frac{10^3}{3!} = 0.00757

P(X \leq 3) =0.0000454+ 0.000454 + 0.00227 + 0.00757 = 0.01034

3. The expected no. of arrivals in a 15 second period is = 10 \times \frac{1}{4} = 2.5. So if Y be the random variable denoting number of passengers arriving in 15 seconds,

Y \sim Poi(2.5)

P(Y=0) = e^{-2.5} \frac{2.5^0}{0!} = 0.0821

4. Here we use the fact that Y can take values 0,1, \dotsc. So, the event that "Y is either 0 or \geq 1" is a sure event ( i.e it has probability 1 ).

P(Y=0) + P(Y \geq 1) = 1 \implies P(Y \geq 1) = 1 -P(Y=0) = 1 - 0.0821 = 0.918

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3 years ago
Given the function f(x) = -5|x + 1 + 3, for what values of x is f(x) = -12?
omeli [17]
<h3>F(x) = - 5(x+1+3)</h3>

or, - 12= - 5x-5-15

or, - 12= - 5x-20

or, - 12+20= - 5x

or, 8= - 5x

or, x= 8÷-5

Also,

F(x)= - 5(x+1+3)

or, f(8÷-5)= - 5(8÷-5+1+3)

= - 5(8-5-15÷-5)

= - 5×-12÷-5

= - 12 #

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3 years ago
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r-ruslan [8.4K]

7+n/2=10

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PtichkaEL [24]

Answer:

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Step-by-step explanation:

Step 1: Subtract -6x from both sides.

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Step 2: Factor left side of equation.

(5x - 4) (x + 2) = 0

Step 3: Set factors equal to 0.

5x - 4 = 0 or x + 2 = 0

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