Question

A proton initially has and then 8.00 s later has (in meters per second). (a) For that 8.00 s, what is the proton's average acceleration in unit vector notation, (b) in magnitude, and (c) the angle between and the positive direction of the x axis

Answer 1

Answer:

Some details are missing in the question, here are the details ; A proton initially has v = -6.5i + 17j + 13k and then 8.00s later has v = -2.8i + 17j - 9.3k (in meters per seconds).

a) proton's average acceleration in unit vector notation = 0.46i - 2.78k

b) Magnitude = 2.85m/s2

c) angle between and the positive direction of the x axis = 279.39 degree (counter clockwise)

Step-by-step explanation:

The detailed and step by step explanation is as shown in the attachment