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4 years ago

Find the distance between (8,-4,7) and (8,5,3)

Mathematics

1 answer:

Tems11 [23]4 years ago

4 0

Answer:

sqrt(97)

Step-by-step explanation:

Since the x for both of the points are the same, we can reduce the problem to "find the distance between (-4, 7) and (5, 3)".

To do that, we can use the Pythagorean theorem, where <em>(change in x)^2+(change in y)^2 = (distance)^2:</em>

(5-(-4))^2+(3-7)^2=d^2

(9)^2+(-4)^2=d^2

81+16=d^2

97=d^2

d=sqrt(97).

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Rearranging formula

allochka39001 [22]

Answer:

Arlo's weight = 52.3 kg

Explanation:

Let Arlo be "x"

Then,

Arlo = x

Bert = x+20 (Because Bert is 20 heavier than Arlo)

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228 = 3x + 35 + $\frac{x+20}{2}$

228 - 3x - 35 = $\frac{x+20}{2}$

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2(193 - 3x) = x + 20

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3 years ago

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Step-by-step explanation:

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Q3.

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Answer:

x = 12

Step-by-step explanation:

Given x varies as the cube root of y then the equation relating them is

x = k $\sqrt[3]{y}$ ← k is the constant of variation

To find k use the condition x = 6 when y = 8, thus

k = $\frac{x}{\sqrt[3]{y} }$ = $\frac{6}{\sqrt[3]{8} }$ = $\frac{6}{2}$ = 3

x = 3 $\sqrt[3]{y}$ ← equation of variation

When y = 64, then

x = 3 × $\sqrt[3]{64}$ = 3 × 4 = 12

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