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3 years ago

Solve using quadratic equation by factoring. x^2-9x=-14

Mathematics

2 answers:

Usimov [2.4K]3 years ago

7 0

Answer:

x= 2 or 7

Step-by-step explanation:

Steps are in the photo I attached

Sonbull [250]3 years ago

5 0

Answer:

2,7

Step-by-step explanation:

See image below:)

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The table showed price paid per concert ticket on a popular online auction site. What was the average price paid per ticket

allochka39001 [22]

Answer: Can you upload a picture of the question?

Step-by-step explanation:

6 0

3 years ago

PLEASE HELP 30 POINTS Wendell is looking over some data regarding the strength, measured in Pascals (Pa), of some building mater

jarptica [38.1K]

Logarithmic functions and exponential functions are inverse and opposite of one another

The logarithmic function is $y = \log_2(x)$ , and the length at 8 pascals is 3 units

<h3>How to determine the logarithmic function</h3>

The exponential function is given as:

$f(x) = 2^x$

Express f(x) as y

$y = 2^x$

Swap the positions of x and y

$x = 2^y$

Take the logarithm of both sides

$\log(x) = \log(2^y)$

Apply the rule of logarithm

$\log(x) = y\log(2)$

Divide both sides by log(2)

$y = \frac{\log(x)}{\log(2)}$

Apply the change of base rule of logarithm

$y = \log_2(x)$

When the strength is 8 pascals, we have:

$y = \log_2(8)$

Express 8 as 2^3

$y = \log_2(2^3)$

So, we have:

$y =3 \log_2(2)$

Evaluate log 2 base 2

$y =3$

Hence, the logarithmic function is $y = \log_2(x)$ , and the length at 8 pascals is 3 units

Read more about logarithmic and exponential functions at:

brainly.com/question/11464095

7 0

2 years ago

Write as an equation: Alice, Barbara, and Carol are sisters. Alice is 3 years younger than Barbara, and Barbara is 5 years young

Dmitrij [34]

a+b+c=68

b-3=a

c-5=b

now just solve the system of equations, substitue so that there are only b's in the equation:

a+b+c=68

(b-3) + b + (b+5) = 68

3b=66

b=22

Therefore Barbara is 22

4 0

3 years ago

Please really need help on this please

Vika [28.1K]

0,1 0,7 I think I use to do these

8 0

3 years ago

Help answering this simple Series Question? I don't know what I did wrong!

Tatiana [17]

Looks like you just evaluated the summand for the given value of $n$ , whereas the question is asking you to find the value of the sum for the first $n$ terms.

Let $S_k=\displaystyle\sum_{n=1}^k\frac3{(-2)^n}$ . Then $S_k$ is the $k$ th partial sum.

$S_1$ happens to be the first term in the series, which is why that box is marked correct:

$S_1=\displaystyle\sum_{n=1}^1\frac3{(-2)^n}=\frac3{(-2)^1}=-1.5$

But the next partial sum is not correct:

$S_2=\displaystyle\sum_{n=1}^2\frac3{(-2)^n}=\frac3{(-2)^1}+\frac3{(-2)^2}=-0.75$

and this is not the same notion as the second term (which indeed is 0.75) in the series.

5 0

3 years ago