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rusak2 [61]
3 years ago
8

5/3=23/6n+7/4-7/2n How to solve?

Mathematics
1 answer:
ser-zykov [4K]3 years ago
7 0

\dfrac{5}{3}=\dfrac{23}{6}n+\dfrac{7}{4}-\dfrac{7}{2}n\\\\LCM(2,\ 3,\ 4,\ 6)=12\\\\\dfrac{5}{3}=\dfrac{23}{6}n+\dfrac{7}{4}-\dfrac{7}{2}n\ \ \ \ |\cdot12\\\\12\cdot\dfrac{5}{3}=12\cdot\dfrac{23}{6}n+12\cdot\dfrac{7}{4}-12\cdot\dfrac{7}{2}n\\\\4\cdot5=2\cdot23n+3\cdot7-6\cdot7n\\\\20=46n+21-42n\\\\20=4n+21\ \ \ \ |-21\\\\-1=4n\ \ \ \ |:4\\\\\boxed{n=-\dfrac{1}{4}}

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Simplify the expression by combining like terms:<br> 5c2 + 13c + 4 – 7c + 9
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Answer:

5c^2 +6c +13

Step-by-step explanation:

so we can see than 5c^2

and 13c - 7c are the same = 6c

and 4 +9 = 13

so answer will 5c^2 +6c +13

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3 years ago
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The area of a trapezium is 800 cm2
svlad2 [7]

Answer:

The distance between the parallel sides is 20cm.

Step-by-step explanation:

Area of a trapezoid:

A=\frac{a+b}{2}\times h

where a and b are the 2 bases, and h is the height. The value we're trying to find here is the height.

3 of the 4 variables in this equation are already given:

A = 800

a = 48

b = 32

Just plug those in and solve for h:

\rightarrow 800=\frac{48+32}{2}\times h\\\rightarrow 800=\frac{80}{2}\times h\\\rightarrow 800=40\times h\\\rightarrow 800\div40=h\\\rightarrow h=20

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3 years ago
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Find the slope of the line #3 and 4 please:))
Leokris [45]

Answer:

#3 - y=4

#4 - x=-1

Step-by-step explanation:

With #3 you are only puting the y-value.

With #4 you are only putting the x-value.

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4 years ago
Molly baked 24 blueberry muffins, 28 banana muffins, and 12 apple muffins. She wants to package them for a bake sale. Each packa
tiny-mole [99]
Find the highest common factor 
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3 0
3 years ago
Solve the following inequality using both the graphical and algebraic approach: 0.5 x + 3 greater-than-or-equal-to 2 x minus 1.5
Liono4ka [1.6K]

Answer:

d. x les-than-or-equal-to 3 Graph B

Graph B expressed as follows; The graph on the coordinate plane, a line goes through (0, 3) and (4, 5). Another line goes through (1, 0.5), and (4, 6.5). The lines intersect at (3, 4.5)

Step-by-step explanation:

The given inequality is expressed as follows;

0.5·x + 3 ≥ 2·x - 1.5

Let y₁ = 0.5·x + 3, and y₂ = 2·x - 1.5, we get;

For x = -1, 0, 1, 2, 3, 4, 5, 6

y₁ = 2.5, 3, 3.5, 4, 4.5, 5, 5.5, 6

y₂ = -3.5, -1.5, 0.5, 2.5, 4.5, 6.5, 8.5, 10.5

From the given data, the lines intersect at (3, 4.5)

The graph on the coordinate plane, a line goes through (0, 3) and (4, 5). Another line goes through (1, 0.5), and (4, 6.5). The lines intersect at (3, 4.5)

Please find attached the required inequality created with MS Excel

Therefore, we have;

3 + 1.5 ≥ 2·x - 0.5·x

4.5 ≥ 1.5·x

∴ 3 ≥ x

x ≤ 3

Therefore, with (typographical) correction, the best option is x les-than-or-equal-to 3 Graph B

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3 years ago
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