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2 years ago

5/3=23/6n+7/4-7/2n How to solve?

Mathematics

1 answer:

ser-zykov [4K]2 years ago

7 0

$\dfrac{5}{3}=\dfrac{23}{6}n+\dfrac{7}{4}-\dfrac{7}{2}n\\\\LCM(2,\ 3,\ 4,\ 6)=12\\\\\dfrac{5}{3}=\dfrac{23}{6}n+\dfrac{7}{4}-\dfrac{7}{2}n\ \ \ \ |\cdot12\\\\12\cdot\dfrac{5}{3}=12\cdot\dfrac{23}{6}n+12\cdot\dfrac{7}{4}-12\cdot\dfrac{7}{2}n\\\\4\cdot5=2\cdot23n+3\cdot7-6\cdot7n\\\\20=46n+21-42n\\\\20=4n+21\ \ \ \ |-21\\\\-1=4n\ \ \ \ |:4\\\\\boxed{n=-\dfrac{1}{4}}$

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skelet666 [1.2K]

Answer:

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Step-by-step explanation:

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

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But we know which value of z satisfy the previous equation so then we can do this:

$z=-0.842$

And if we solve for a we got

$a=30 -0.842*7.8=23.432$

So the value of height that separates the bottom 20% of data from the top 80% is 23.432.

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