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Salsk061 [2.6K]
3 years ago
15

Who’s the the y-value of the vertex of the function f(x)=-(x+8)(x-14)

Mathematics
1 answer:
Ksju [112]3 years ago
5 0

Answer:

The required y-value is -121.

Step-by-step explanation:

There are several ways in which we could approach this problem.  From the two binomial factors (x + 8) and (x - 14), we know that the two roots are x = -8 and x = 14.  The axis of symmetry is the vertical line x = 3.  This value is halfway between x = -8 and x = 14.

Substituting x = 3 into  f(x)= -(x+8)(x-14) results in f(3) = -(11)(-11) = -121.

The vertex is at (3, -121).  The required y-value is -121.

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Which equation represents a parabola that opens upward, has a minimum at x = 3, and has a line of symmetry at x = 3?
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Answer:

A.\ y = x^2 - 6x + 13 is the correct answer.

Step-by-step explanation:

We know that vertex equation of a parabola is given as:

y = a(x-h)^2+k

where (h,k) is the vertex of the parabola and

(x,y) are the coordinate of points on parabola.

As per the question statement:

The parabola opens upwards that means coefficient of x^{2} is positive.

Let a = +1

Minimum of parabola is at x = 3.

The vertex is at the minimum point of a parabola that opens upwards.

\therefore h = 3

Putting value of a and h in the equation:

y = 1(x-3)^2+k\\\Rightarrow y = (x-3)^2+k\\\Rightarrow y = x^2-6x+9+k

Formula used: (a-b)^2=a^{2} +b^{2} -2\times a \times b

Comparing the equation formulated above with the options given we can observe that the equation formulated above is most similar to option A.

Comparing y = x^2 - 6x + 13 and y = x^2-6x+9+k

13 = 9+k

k = 4

Please refer to the graph attached.

Hence, correct option is A.\ y = x^2 - 6x + 13

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