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Nonamiya [84]
3 years ago
6

Can someone please help me?

Mathematics
1 answer:
Sliva [168]3 years ago
3 0

Answer:

a^{2}+b^{2} =c^{2} { Pythagorean Theorem}

{Division property of Equality}

sin 0=a/c{definition of sin0)

cos0=b/c{definition of cos0)

{Substitution}

Step-by-step explanation:

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5 0
3 years ago
As a promotion, a clothing store draws the name of one of its customers each week. The prize is a coupon for the store. If the w
kompoz [17]

The given formula is f(x) = 20(1.2)^x

The formula is the starting amount multiplied by 1 + the percentage raised to the number of weeks.


A) the percent increase is 20% ( 1.2 in the formula is 1 +20% as a decimal)

B) the original amount is $20

C) for 2 weeks, replace x with 2 and solve:

20(1.2)^2

20(1.44) = $28.80

After 2 weeks the coupon is $28.80

D)  To solve for the number of weeks (x) set the equation equal to $100:

100 = 20(1.2)^x

Divide both sides by 20:

5 = 1.2^x

Take the natural logarithm of both sides:

ln(5) = ln(1.2^x)

Use the logarithm rule to remove the exponent:

ln(5) = x ln(1.2)

Divide both sides by ln(1.2)

x = ln(5) / ln(1.2)

Divide:

X = 8.83

At 8.83 weeks the coupon would be $100, so after 9 weeks the coupon would be greater than $100

The answer is 9 weeks.

4 0
3 years ago
URGENT DUE BY 1:00 FOR MY FINAL GRADE PLEASE HELP OR I WILL FAIL SEMESTER WILL RATE GOOD THX BLESS YOU!!!!
Lesechka [4]
F(x) = 3x + 11
Is the function used to show this.

when you know this, you are able to do the following:
f(10) = 30 + 11 = $41
That would be the allowance of the 10th week.

The question, however wants the total.

This again, can be done like this:
f(1) + f(2) + f(3) + f(4) + f(5) + f(6) + f(7) + f(8) + f(9) + f(10) = $275 :)
14 + 17 + 20 + 23 + 26 + 29 + 32 + 35 + 38 + 41 = $275

Sure there is a better formula, but i couldnt seem to make it, sorry.

HUGE UPDATE: The sum is $275 not 200..


3 0
3 years ago
Read 2 more answers
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