Answer:
128
6
12
48
Step-by-step explanation:
When reflecting across the Y axis, the Y values remain the same.
Now if you were reflecting across Y = 0, the x values would just be inverse ( opposite signs).
So this triangle if reflected across Y = 0 the new vertices would be (4,4) (2,3) and (5,2)
Now since the reflection line is y = -1, which is a one unit shift to the left of y = 0, subtract 1 unit from each X value.
The locations are now: A'(3,4), B'(1,3) and C'(4,2)
Answer:
3 (negative 64 divided by 8) + 25 = 1
Step-by-step explanation:
Negative 4 + (negative 5) (negative 6) divided by (negative 3) = -4 + (-5)(-6)/(-3) = -4 + 30/-3 = -4 - 10 = -14
8 Left-bracket 10 divided by (2) (negative 2) Right-bracket = 8(10/((2)(-2)) = -20
3 (negative 64 divided by 8) + 25 = 3(-64/8) + 25 = 3(-8) + 25 = -24 + 25 = 1
Negative 2 (negative 5) (negative 3) divided by 10 = (-2)(-5)(-3)/10 = -3
The only positive value here is 1, which is a result of 3 (negative 64 divided by 8) + 25