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Tanzania [10]
4 years ago
6

What decimal number is the smallest 1.001, 1.1, 1.01, or 1.011

Mathematics
1 answer:
Elan Coil [88]4 years ago
8 0
The first one 1.001, because the zeros in front make it smaller
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Select all the ratios equivalent to 8:6.<br><br>A. 4:3<br>B. 6:8<br>C. 16:12<br>D. 10:8<br>E. 7:5​
omeli [17]

9514 1404 393

Answer:

  A, C

Step-by-step explanation:

The given ratio can be reduced by removing a factor of 2 from each element.

  8 : 6 = 4 : 3 . . . . matches A

It can be put in other forms by multiplying each element by the same factor. Using a factor of 2 on the original ratio values, we get ...

  8 : 6 = 16 : 12 . . matches C

__

Any ratio that doesn't reduce to the integer ratio 4 : 3 is not equivalent. The ratio with elements reversed (3:4) is not equivalent.

7 0
3 years ago
Is 127 rational or irrational​
ruslelena [56]

Answer:

rational

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Sherry claims that the expression 1/x will always be equivalent to a repeating decimal whenever x is an odd number greater than
fomenos

Answer:

The correct options are :

b. 5

e. 25

Step-by-step explanation:

The question is incomplete. The missing part is :

'' Which of these values will prove Sherry's claim is false :

a. 3

b. 5

c. 7

d. 11

e. 25 ''

One way to prove that Sherry's claim is false is finding one odd number greater than 1 that when we replace it in the denominator of the expression \frac{1}{x} the result isn't equivalent to a repeating decimal.

Let's analyze each option :

  • a. 3

3 is an odd number greater than 1 ⇒ If we replace in the expression \frac{1}{x} ⇒

\frac{1}{3}  ≅ 0.3333 (repeating decimal)

The option a. 3 won't prove that Sherry's claim is false.

  • b. 5

5 is an odd number greater than 1 ⇒ If we replace in the expression \frac{1}{x} ⇒

\frac{1}{5}=0.2

The result isn't a repeating decimal.

The option b. 5 will prove that Sherry's claim is false.

  • c. 7

7 is an odd number greater than 1 ⇒ If we replace in the expression \frac{1}{x} ⇒

\frac{1}{7} ≅ 0.1428 (repeating decimal)

The option c. 7 won't prove that Sherry's claim is false.

  • d. 11

11 is an odd number greater than 1 ⇒ If we replace in the expression \frac{1}{x} ⇒

\frac{1}{11} ≅ 0.0909 (repeating decimal)

The option d. 11 won't prove that Sherry's claim is false.

  • e. 25

25 is an odd number greater than 1 ⇒ If we replace in the expression \frac{1}{x} ⇒

\frac{1}{25} ≅ 0.04

The result isn't a repeating decimal

The option e. 25 will prove that Sherry's claim is false.

3 0
3 years ago
We can calculate the depth d of snow, in centimeters, that accumulates in Harper's yard during the first h hours of a snowstorm
PtichkaEL [24]

We are given an equation d = 5h, where d is the depth of snow and h is the number of hours of a snowstorm.

We need to find the number of hours of a snowstorm that accumulate the  snow to 1 centimeter.

In order to find the number of hours that accumulate the  snow to 1 centimeter, we need to plug d=1 in the given equation.

On plugging d=1, we get

1= 5h.

Dividing both sides by 5, we get

1/5 = h.

<h3>Therefore, it would take 1/5 hour for 1 centimeter of snow to accumulate in Harper's yard</h3>
4 0
3 years ago
Read 2 more answers
Need it please help me​
Fynjy0 [20]
The answer to the question is the third one I’m pretty sure
3 0
3 years ago
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