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just olya [345]
3 years ago
7

There are 15 European cities that Kevin would eventually like to visit. On his next vacation, though, he only has time to visit

4 of the cities: one on Monday, one on Tuesday, one on Wednesday, and one on Thursday. He is now trying to make a schedule of which city he'll visit on which day. How many different schedules are possible?
Mathematics
1 answer:
antoniya [11.8K]3 years ago
6 0

Answer:

32760 different schedules are possible.

Step-by-step explanation:

The order is important.

For example

Prague on Monday, Berlin on Tuesday, Liverpool on Wednesday and Athens on Thursday is a different schedule than Berlin on Monday, Prague on Tuesday, Liverpool on Wednesday and Athens on Thursday.

So we use the permutations formula to solve this question.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

P_{(n,x)} = \frac{n!}{(n-x)!)}

How many different schedules are possible?

Choose 4 cities among a set of 15. So

P_{(15,4)} = \frac{15!}{(15-4)!)} = 32760

32760 different schedules are possible.

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In this question the given information's should be closely noted. The length and width of the perimeter are already given. Based on those information's the answer to the question can be easily deduced.
Length of the rectangle = 2 1/2 inch
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Width of the rectangle = 5 1/3 inch
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