The problem statement gives a relation between the amount removed from one bag and the amount removed from the other. It asks for the amount remaining in each bag. Thus, there are several choices for variables in this problem, some choices resulting in more complicated equations than others.
Let's do it this way: let x represent the amount remaining in bag 1. Then the amount removed from bag 1 is (100-x). The amount remaining in bag 2 is 2x, so the amount removed from that bag is (100-2x). The problem statement tells us the relationship between amounts removed:
... (100 -x) = 3(100 -2x)
... 100 -x -3(100 -2x) = 0 . . . . . . subtract the right side
... 5x -200 = 0 . . . . . . . . . . . . . . eliminate parentheses and collect terms
... x -40 = 0 . . . . . . . . . . . . . . . . .divide by 5
... x = 40 . . . . . . . . . . . . . . . . . . . add 40
- 40 kg is left in the first bag
- 80 kg is left in the second bag
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<u>Check</u>
The amount removed from the first bag is 60 kg. The amount removed from the second is 20 kg. The amount removed from the first bag is 3 times the amount removed from the second bag, as described.
Answer:
a=-1.2
Step-by-step explanation:
5x-10=3x+a=12
let's first find x:
5x-10=12
add 10 to both sides:
5x=22
divide both sides by 5:
x=4.4
now that we know what x is, we can plug it back into the equation to find a:
3*4.4+a=12
first, simplify both sides:
13.2+a=12
then, subtract 13.2 from both sides:
and our answer is: a=-1.2
Answer:
-3
Step-by-step explanation:
Unless x has a number she owes them 3 dollars.
