Answer:
3;1
Step-by-step explanation:
6. It is asking you to find the surface area for this one:
1 litre = 0.001 cubic meters
15.4 litres = 0.0154 cubic meters
The volume of the cylinder has to be 0.0154m^3.
V = (pi(r)^2)h
0.0154 = (pi(r)^2)(1)
r^2 = 0.0154/pi
r = 0.07m
Surface Area of Circles on Bottom:
A = pi(r)^2
A = pi(0.07)^2
A = 0.0154
0.0154*2 = 0.0308m^2
Surface Area of Walls:
This will be the circumference of the circle times the height, since the walls are just like a big rectangle.
C = 2pi(r)
C = 2pi(0.07)
C = 0.44m
0.44*1 = 0.44m^2
Finally, add the two surface areas:
0.44 + 0.0308 = 0.47m^2
You will need 0.47m^2 of sheet metal to make this cylinder.
7. Find the volume of everything and just the graphite, and subtract the graphite’s volume from everything to get just the wood. The volume of a cylinder is pi((r)^2)h.
Everything:
Watch out for units, since the diameter is in mm and the length is in cm.
r = 3.5mm or 0.35cm
V = pi((0.35)^2)(14)
V = 5.34cm^3
Graphite:
r = 0.5mm or 0.05cm
V = pi((0.05)^2)(14)
V = 0.11cm^3
5.34 - 0.11 = 5.23cm^3
8. For this problem, it wants your answer in cm^3. Find the volume of one bowl and multiply it by 250:
r = 3.5cm
V = pi((3.5)^2)(4)
V = 153.94cm^3
153.94*250 = 38484.51cm^3 of soup needed.
I sure hope that I didn’t confuse you too much with all of my math gibberish (sorry). Please let me know if there is anything else that I can help with. Have a nice day
2+0+1+5x3= 24 and
6+4+1+3x3=42 than
<span>1+1+2+8x3=36
Final Answer 36
:D Welcome</span>
Answer:
Step-by-step explanation:
Sin theta is the ratio of side opposite over hypotenuse of a reference angle situated at the origin in an x-y coordinate plane. If sec theta is negative, then the only quadrant where sin is positive AND sec is negative is quadrant 2. Remember that sec theta is the inverse of cos theta. Puttling our right triangle in QII, the side measuring 7 is across from the angle and the hypotenuse is 11. In order to find the cos theta and tan theta, we need the side adjacent to the angle. Use Pythagorean's Theorem to find the side adjacent.
and
and
so
Remember that this value is why the sec is negative. Because x is negative in QII, the cos theta is side adjacent over hypotenuse:
and
But we should probably rationalize that denominator, so
