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3 years ago

What is the reason for number 4 and 5?

Mathematics

1 answer:

Fiesta28 [93]3 years ago

3 0

Answer:

4. QT and RT are 2 sides of an equilateral triangle.

5. Congruent by SAS

Step-by-step explanation:

All sides of an equilateral triangle are equal in length.

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If the bug jumps 7 units and lands at 0, where could it have started?

fenix001 [56]

The answer is -7 jzzoksjsjs

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2 years ago

Read 2 more answers

What does the quantity 28-8 represent?

nikklg [1K]

You question implies simple subtraction is needed:

28-8=20

5 0

2 years ago

The walking distance that is saved by cutting across the lot is

dezoksy [38]

Using the Pythagorean Theorem, we have x^2+(x+2)^2=51^2, and
x^2+ x^2+4x+4=2x^2+4x+4=51^2. After that, we subtract 51^2 from both sides to get 2x^2+4x-2597. Using the quadratic formula (x=(-b+-sqrt(b^2-4ac))/2a in ax^2+bx+c), we get around 35 for x. We did + instead of minus after b due to that it can't be negative! x+2=37, so you save 35+37-51=around 21 feet

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2 years ago

Three friends each have some ribbon. Carol has 90 inches of ribbon, Tino has 7.5 feet of ribbon, and Baxter has 3.5 yards of rib

erastovalidia [21]

Answer: 306 inches or 25.5 feet or 8.5 yards.

Step-by-step explanation:

Given: Carol has 90 inches of ribbon, Tino has 7.5 feet of ribbon, and Baxter has 3.5 yards of ribbon.

1 feet = 12 inches

length of ribbon Tino has = 12 x 7.5 = 90 inches

1 yard = 36 inches

length of ribbon Baxter has = 3.5 x 36 = 126 inches

Total ribbon they have = (length of ribbon Carol has) + (length of ribbon Tino has) + (length of ribbon Baxter has)

= (90+90+126) inches

= 306 inches

In feet , Total ribbon = $\dfrac{306}{12}\text{ feet}$ $[\text{ 1 inch}=\dfrac{1}{12}\text{ feet}]$

$=\text{25.5 feet}$

In yards, Total ribbon = $\dfrac{25.5}{3}\text{ yards}$ $[\text{1 feet}=\dfrac{1}{3}\text{ yard}]$

$=\text{ 8.5 yards}$

Hence, the total length of ribbon the three friends have is 306 inches or 25.5 feet or 8.5 yards.

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3 years ago

The graph above is a transformation of the function x2 Write an equation for the function graphed above

lutik1710 [3]

Answer: y=0,5x²-x-1,5.

Step-by-step explanation:

$(-1;0)\ \ \ \ (3;0)\ \ \ \ (1;-2) \ \ \ \ y=ax^2+bx+c\ ?\\\left\{\begin{array}{ccc}a*(-1)^2+b*(-1)+c=0\\a*3^2+b*3+c=0\\a*1^2+b*1+c=-2\end{array}\right \ \ \ \ \ \left\{\begin{array}{ccc}a-b+c=0\ \ (1)\\9a+3b+c=0\ (2)\\a+b+c=-2\ (3)\end{array}\right \\$