Question

Can someone please help I need a clear explanation on how to solve this equation.

Answer 1

B = amount of students who chose Bulldog

n = amount of students who chose lion

t = amount of students who chose tiger

so.. "t" chose tiger, ok

"Four times as many students chose Bulldog as chose Tiger"
namely, if "t" chose tiger, then 4 times that many chose Bulldog, thus

b = 4t

"Twice as many students chose Lion as chose Tiger"
namely, if "t" students chose tiger, twice as many chose lion

n = 2t

now, we know a total of 273 students were surveyed, thus

$\bf \begin{cases} b+n+t=273\\ \boxed{4t}+\boxed{2t}+t=273 \end{cases} \\\\\\ 7t=273\implies t=\cfrac{273}{7}\impliedby \textit{that many chose \underline{tiger}}$

Answer 2

Answer:

78 students chose lion.

Step-by-step explanation:

Let x students chose tiger.

Let y students chose bull dog.

Let z students chose lion.

Total students = 273

$x+y+z=273$           ....(1)

Four times as many students chose Bulldog as chose Tiger.

$y=4x$

Twice as many students chose Lion as chose Tiger.

$z=2x$

Substituting the values of y and z in (1)

$x+4x+2x=273$

=> $7x=273$

x = 39   (students who chose tiger)

We have to find students who chose Lion or z (defined above)

$z=2x$

$z=2(39)$

So, z = 78

Therefore, 78 students chose lion.