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kifflom [539]
4 years ago
7

Draw the reflected image of ABCD over line l.

Mathematics
2 answers:
Masteriza [31]4 years ago
8 0

Answer

i woukldnt know

Step-by-step explanation:

ahahahahahahahahahahahahhahahahahaha

Alina [70]4 years ago
5 0

Answer: The second image, the second image where b' is right above b is the correct answer for this, hope this helped!

<!> Brainliest is appreciated! <!>

Step-by-step explanation:

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Suppose a sample of 60 business majors revealed that the average time spent studying per week is 22 hours with a standard deviat
trapecia [35]
IDK I don't why I'm answering cuz yeah n IDK xD
4 0
4 years ago
Find the missing value 8- = -5​
podryga [215]

Answer:

x = 13

Step-by-step explanation:

call the missing number x

8 - x = - 5                        Subtract 8 from both sides

8-8 - x = -5-8                  Combine

-x = - 13                           Multiply by -1

x = 13

6 0
3 years ago
A certificate of deposit with $600 principal earns 2. 5% interest for 6 years. How much is the interest earned for 6 years?
mario62 [17]

~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$600\\ r=rate\to 2.5\%\to \frac{2.5}{100}\dotfill &0.025\\ t=years\dotfill &6 \end{cases} \\\\\\ I = (600)(0.025)(6)\implies I=90

5 0
2 years ago
What is the 11th term of this geometric sequence?: 16384, 8192, 4096, 2048
Scrat [10]

Answer:

16

Step-by-step explanation:

1) Find out r of the sequence. The first term(a1) is 16384, the second term (a2) is 8192.

8192=16384*r. r= 0.5

2) Use the rule that an=a1*r^(n-1)

a11=a1*r^10

a11= 16384*((0.5)^10)= 16384/ (2^10)=16.

3 0
3 years ago
An article presents a study of the failure pressures of roof panels. Following are the failure pressures, in kPa, for five panel
Maru [420]

Answer:

95% confidence interval: (2.339,3.521)

Step-by-step explanation:

We are given the following in the question:

3.32, 2.49, 3.45, 2.38, 3.01

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

\bar{x} =\displaystyle\frac{14.65}{5} = 2.93

Sum of squares of differences = 0.925

\sigma = \sqrt{\frac{0.925}{4}} = 0.48

95% confidence interval:

\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

t_{critical}\text{ at degree of freedom 4 and}~\alpha_{0.05} = \pm 2.77  

2.93 \pm 2.77(\frac{0.48}{\sqrt{5}} ) = 2.93 \pm 0.591 = (2.339,3.521)

7 0
3 years ago
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