Answer:
C and D
Step-by-step explanation:
5^3 - 5^0 = 125 - 1 = 124, so it's not A
5^12 / 5^4 = 5^(12-4) = 5^8, so it's not B
5^7 * 5^-4 = 5^(7+(-4)) = 5^3, so it can be C
5^0 * 5^3 = 5^(0+3) = 5^3, so it can be D
5 + 5^2 = 5 + 25 = 30, so it can't be E
A) No one in the class studied more then 5 hours
Answer:
768
Step-by-step explanation:
64*12
So have the sequence:

To check if the sequence is geometric, we are going to find its common ratio; to do it we are going to use the formula:

where

is the common ratio

is the current term in the sequence

is the previous term in the sequence
In other words we are going to divide the current term by the previous term a few times, and we will to check if that ratio is the same:
For

and

:


For

and

:


For

and

:


As you can see, we have a common ratio!
We can conclude that our sequence is a geometric sequence and its common ratio is