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xeze [42]
3 years ago
14



Mathematics
2 answers:
igomit [66]3 years ago
5 0

Answer:

A) F(x) < 0 over the intervals (-∞, -0.7) and (0.76, 2.5)

Step-by-step explanation:

Here f(x) represents the y axis.

The value of f(x) is negative over the intervals (-∞, -0.7) and (0.76, 2.5).

You can see in the graph f(x) below 0.

Therefore, the answer is A) F(x) < 0 over the intervals (-∞, -0.7) and (0.76, 2.5)

Hope this will helpful.

Thank you.

Olegator [25]3 years ago
3 0

Answer:

Option A.

Step-by-step explanation:

Given graph represents the function F(x).

If the graph of F(x) is below the x-axis then F(x)<0.

If the graph of F(x) is above the x-axis then F(x)>0.

The graph of F(x) intersect the x-axis at -0.7, 0.76 and 2.5.

From the given graph it is clear that

F(x)<0 over the interval (-∞,-0.7).

F(x)>0 over the interval (-0.7,0.76).

F(x)<0 over the interval (0.76,2.5).

F(x)>0 over the interval (2.5,∞).

Since F(x) < 0 over the intervals (-∞, -0.7) and (0.76, 2.5), therefore, the correct option is A.

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<h3>Answer: Choice D. \angle SQR \cong \angle XQR</h3>

The red angle markers show those two angles are congruent. That's one "A" of "ASA". The S refers to a congruent pair of sides. We don't have any tickmarks to indicate congruent pairs; however, we do know that QR = QR is a shared side that overlaps (reflexive theorem). So this is the "S" in "ASA".

The thing missing is the angle Q of the top triangle, and also of the bottom triangle as well. If we know those two angles are congruent, then we have enough info to use ASA. More specifically, if we know that \angle SQR \cong \angle XQR, then we can use ASA.

One thing to notice is that the other answer choices involve side lengths and not angles. This implies that if A, B or C were one of the answers, then we would have something like SAS or SSS. But instead we want ASA. So we can immediately rule choices A,B, and C out.

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