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gavmur [86]
3 years ago
5

Add 14 to the quotient of 42 and 6, then double the result

Mathematics
1 answer:
PolarNik [594]3 years ago
3 0
The answer is 42 why, because 42 divided by 6 equals 7 plus 14 is 21 and then you double it so it's 42.
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These are the travel times to work for a class of 20 people in minutes. 80 15 60 55 120 95 30 20 90 50 85 45 40 20 85 75 130 20
alexira [117]

Answer:

115 minutes

Step-by-step explanation:

Range = highest observation - smallest observation

Highest observation = 130 minutes

Smallest observation = 15 minutes

Therefore range = 130 - 15

=115 minutes

8 0
3 years ago
How would you write 2/5 as a decimal
kondaur [170]
<span>2/5 as a decimal?
2/5 =0.4
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7 0
3 years ago
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Celia thinks that because the drop between the first two points is so large, the best model might actually have a y- intercept a
victus00 [196]

The equation of Celia's exponential model is y = 9.4 * 0.75^x

<h3>How to estimate the model?</h3>

The table that completes the question is added as an attachment

The y-intercept is given as:

(0,9.4)

The ratios of successive data values are calculated as:

r_1 = \frac{6.0}{10}= 0.6

r_2 = \frac{5.4}{6.0}= 0.9

r_3 = \frac{3.9}{5.4}= 0.72

r_4 = \frac{3.7}{3.9}= 0.95

r_5 = \frac{2.3}{3.7}= 0.62

r_6 = \frac{1.4}{2.3}= 0.61

r_7 = \frac{1.0}{1.4}= 0.71

r_8 = \frac{0.9}{1.0}= 0.9

r_9 = \frac{0.8}{0.9}= 0.89

r_{10} = \frac{0.5}{0.8}= 0.63

The average of the above values is

b = \frac{0.6 + 0.9 + 0.72 + 0.95 + 0.62 + 0.61 + 0.71 + 0.9 + 0.89 + 0.63}{10}

Evaluate

b = 0.75

An exponential function is represented as:

y = ab^x

Where

a = 9.4 as in the y-intercept (0,9.4)

b = 0.75

Substitute these values in y = ab^x

y = 9.4 * 0.75^x

Hence, the Celia's exponential model is y = 9.4 * 0.75^x

Read more about exponential function at:

brainly.com/question/11464095

#SPJ1

7 0
2 years ago
What is the function written in vertex form?
bekas [8.4K]
4(x+6)2+10=8x+58
4(x+6)2-26=8x+22
4(x+6)2-134=8x-86
4(x+6)2+154=8x+202
~ I hope this helped!
4 0
3 years ago
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Assume that trees are subjected to different levels of carbon dioxide atmosphere with 6% of the trees in a minimal growth condit
Licemer1 [7]

Answer:

The mean is 561.40 ppm. The standard deviation is 29.15 ppm.

Step-by-step explanation:

We can calculate the mean and the standard deviation using the proportions of the population that are subjected to the different levels.

The mean can be calculated as

\mu=\sum p_i*L_i\\\\\mu=0.06*370+0.13*470+0.46*560+0.35*630\\\\\mu=561.40 \,ppm

The standard deviation of the mean can be calculated in a similar way

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The mean is 561.40 ppm. The standard deviation is 29.15 ppm.

8 0
3 years ago
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