Answer:
Step-by-step explanation:
I assume that the last question should read "cosE"
Answer:
C) 42.14 cm²
Step-by-step explanation:
<u>Recall the area formulas for a square and circle:</u>
Area of square: A=s²
Area of circle: A=πr²
<u>Given:</u>
π=3.14
s=14
r=s/2=14/2=7
Therefore, the area of the square is A=14²=196 cm²
The area of the two semicircles is A=3.14(7)²=3.14(49)=153.86 cm²
Find the difference between the two areas to get the shaded area:
196 - 153.86 = 42.14
Therefore, the shaded area is 42.14 cm², making C the correct choice.
66 degrees divided by 2= 33 degrees
Then, 22/2=11
11/sin(33)= 20.2
Sin 0 =0 that’s your answer
We are given the
perimeter of isosceles trapezoid = 28 in
ratio of length of bases = 5:3
We are to find the lengths of sides of the trapezoid and the diagonal that bisects the angle at the base with a longer length
The formula for the perimeter of an isosceles trapezoid is
P = (1/2) (b1 + b2) h
We are given the ratio
b2/ b1 = 5 /3
b2 = 5/3 b1
Substituting
28 = (1/2) (5/3 b1) h
The height of the trapezoid is expressed in terms of b1
For the diagonal
d² = h² + [(b2 - b1) + (b2 - b1)/2]²
Express h and b2 in terms of b1 and diagonal can be expressed in terms of b1
