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Lesechka [4]
3 years ago
6

Cassie wants to determine the length of the shadow that a 60-foot tall telephone pole casts without measuring it. If Cassie's ma

ilbox, which is 42 inches in height, casts a shadow that is 21 inches in length, how long is the shadow that the telephone pole casts?
Mathematics
1 answer:
Natasha2012 [34]3 years ago
8 0

Answer & Explanation:

Cassie wants to determine the length of the shadow that a 60-foot tall telephone pole casts without measuring it. If Cassie's mailbox, which is 42 inches in height, casts a shadow that is 21 inches in length, how long is the shadow that the telephone pole casts?

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Write an expression using fractions to show how to determine the amount that each person will pay. Then calculate each person's
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The fraction based on the information given illustrated for each person.

<h3>How to illustrate the information?</h3>

Me: $14.89

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Friend 2: $25.67

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Total = $59.42

The fraction for each person will be:

Me: $14.89 = 14.89/59.42 = 0.25

Friend 1: $7.27 = 7.27/59.42 = 0.12

Friend 2: $25.67 = 25.67/59.42 = 0.32

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2 years ago
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Answer:5/12

Step-by-step explanation:

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4 years ago
A nunber greater than 0 is called
kirza4 [7]
Hey there! 

Negatives numbers are less than 0 and positive numbers are  greater  than 0

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Answer: Positive numbers

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3 years ago
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A large box contains 10,000 ball bearings. A random sample of 120 is chosen. The sample mean diameter is 10 mm, and the standard
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Answer:

Option a) A 95% confidence interval for the mean diameter of the 120 bearings in the sample is 10 \pm 1.96\displaystyle\frac{0.24}{\sqrt{120}}.

Step-by-step explanation:

We are given the following information in the question:

Sample size, n = 120

Sample mean = 10 mm

Standard Deviation = 0.24 mm

Formula:

\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

10 \pm 1.96\displaystyle\frac{0.24}{\sqrt{120}}

Hence, the correct interpretation for the confidence interval is given by option a).

A 95% confidence interval for the mean diameter of the 120 bearings in the sample is 10 \pm 1.96\displaystyle\frac{0.24}{\sqrt{120}}.

We have to consider the factor of sampling of 120 ball bearings from a population of 10,000 ball bearings.

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Raul says that –499 is less than –4. Kendall says that –499 is greater than –4. Who is correct, and why?
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Rual because negatives move backwards so the higher the number the smaller it is
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3 years ago
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