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Vinvika [58]
3 years ago
5

3|x+5|=7 Please answer as soon as possible

Mathematics
1 answer:
svet-max [94.6K]3 years ago
3 0

Answer:

The | signs are absolute value signs. Absolute value just makes a negative value turn positive, because technically there is no negative value. For example |-x+5| turns into x+5. If it's already positive, it stays the same. So basically, they're just acting as parenthesis right now. Just distribute the 3 and get 3x+15=7. subtract 17 and get 3x=-8. Divide both sides by three, and you should get x= -8/3. But wait, there's more. Since this is an absolute value equation, there should be more than one answer. Simply make the number on the other side negative. 3x+15=-7. subtract 15 and get -22. Keep going and your answer should be -22/3.

So in conclusion, your two answers are -8/3 and -22/3.

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Sarah took the advertising department from her company on a round trip to meet with a potential client. Including Sarah a total
dimulka [17.4K]
You can set up a system of equations for this problem. x= number of coach tickets and y = number of first class tickets.

$210x + $1200y = $10,230 (cost of coach ticket plus cost of first class tickets is total budget)

x + y = 11 (number of coach tickets plus number of first class tickets is total number of people)

Solve the second equation for y to get y = 11 - x, then plug that into the first equation and solve for x:

$210x + $1200(11 - x) = $10,230

$210x + $13,200 - $1200x = $10,230

-$990x + $13,200 = $10,230

-$990x = $2,970

x = 3


Sarah bought x = 3 coach tickets. Plug that into the second equation and solve for y:

3 + y = 11

y = 8


Sarah bought y = 8 first class tickets.
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Xelga [282]

Answer:

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Step-by-step explanation:

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What two numbers multiply to 630 and add to -57
sveta [45]
-15 and -42 both add to -57 and multiply to 630 
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3 years ago
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Given the equation 2x = 4y - 3 write another linear equation that would create a system that has the number of solutions listed
Harman [31]

Answer:

A. 2x-4y=\pi
B.  x=1

C. 2x-4y=3

Step-by-step explanation:

A. 2x-4y=\pi. Any number could work as long as the coefficients for x and y stays the same. You are basically imposing that the quantity 2x-4y (if you bring 4y to the LHS) is equal to both -3 AND \pi, or any number you like. But yesterday was 3/14 so let's pick a fun number!

B.  x=1 Or y=1. Or as long as you don't pick the same ratios of x and y you're golden. But x=1 is the easiest that comes to mind

C. 2x-4y=3. To get infinitely many solutions you just have to rewrite the equation again. Maybe move things around if you prefer, or multiply everything by a number you lile.

7 0
2 years ago
state domain and range, intercepts, relative max and relative mins points and values, intervals of increase and decrease, interv
Anarel [89]

The domain of the graph is -∝ < x < ∝ and the range of the graph is -∝ < y < ∝. Also, the graph has no axis of symmetry

<h3>The domain and range of the graph</h3>

From the graph, we can see that the x values extend indefinitely

So, the domain of the graph is -∝ < x < ∝

From the graph, we can see that the y values extend indefinitely

So, the range of the graph is -∝ < y < ∝

<h3>The intercepts</h3>

This is where the graph crosses the axes

So, we have the intercepts to be

  • x-intercept = -4, -2 and 2
  • y-intercept = -9

<h3>Relative max and relative mins points and values, </h3>

The graph has a relative maximum at (3, 3) and the relative minimum are (0.5, 10)

<h3>Intervals of increase and decrease, </h3>

There are the intervals where the function increases and decreases

So, we have the intervals to be

  • Increasing interval: (0.5, ∝) and (-∝, -3)
  • Decreasing interval: (-3, 0.5)

<h3>Intervals of positive and negative,</h3>

There are the intervals where the function is positive and negative

So, we have the intervals to be

  • Positive interval: (-4, -2) and (2, ∝)
  • Negative interval: (-∝, -4) and (-2, 2)

<h3>The symmetry</h3>

This is the line that divides the graph equal part

In this case, the graph has no axis of symmetry

<h3>The end behavior</h3>

Using the intervals where the function is positive and negative, the end behavior is

  • As x ⇒ ∝, f(x) ⇒ +∝
  • As x ⇒ -∝, f(x) ⇒ -∝

Read more about functions at:

brainly.com/question/3951754

#SPJ1

3 0
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