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Inessa05 [86]
4 years ago
10

H(n) = 3n - 5; Find h(-9)

Mathematics
2 answers:
marissa [1.9K]4 years ago
6 0

h(n)=3n-5\Longrightarrow h(-9)=3(-9)-5=-27-5=\boxed{-32}

Hope this helps.

wolverine [178]4 years ago
5 0

Answer:

h(-9) is -32

Step-by-step explanation:

Given

h(n) = 2n-5

In order to find the value of function on a specific input, the input is plugged into the function in place of variable. So, if we have to find h(-9), we will put -9 at the place of n.

So,

h(-9) = 3(-9)-5

= -27-5

= -32

Hence, h(-9) is -32 ..

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Given the two vertices and the centroids of a triangle, how many possible locations are there for the third vertex?
hoa [83]

Answer:

  1

Step-by-step explanation:

The centroid is the average of the coordinates of the three vertices. If you know two vertices (A and B) and the centroid (Q), then the third vertex (C) is ...

  C = 3Q -A -B

It has only one possible location.

7 0
3 years ago
The hypotenuse of a right triangle is 50 millimeters long. One leg of the right triangle is 30 millimeters long. What is the len
alexandr1967 [171]
First. we use the Pythagorean theorem:
a {}^{2} +  b {}^{2} =  c {}^{2}
Add the numbers in
{30}^{2}  +  {b}^{2}  =  {50}^{2}
start simplifying
{b}^{2}  = 1600
b = 40

So, the leg has a length of 40 mm.
6 0
4 years ago
Help me!!!
Basile [38]

Answer:

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8 0
3 years ago
Can anyone help me???
natita [175]

Answer:

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5 0
2 years ago
What is the value of a1 of the geometric series? Sigma-Summation Underscript n = 1 Overscript infinity EndScripts 12 (negative o
worty [1.4K]

Answer:

12

Step-by-step explanation:

The given geometric series is

\sum_{n = 1}^{ \infty} 12( { -  \frac{1}{9} })^{n - 1}

We want to determine the first term of this geometric series.

Recall that the explicit formula is

a_{n} = 12( { -  \frac{1}{9} })^{n - 1}

To find the first term, we put n=1 to get:

a_{1} = 12( { -  \frac{1}{9} })^{1 - 1}

This gives us:

a_{1} = 12( { -  \frac{1}{9} })^{0}

a_{1} = 12(1) = 12

Therefore the first term is 12

6 0
4 years ago
Read 2 more answers
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