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IrinaK [193]
4 years ago
13

Does anyone know how to do this I need help

Mathematics
1 answer:
navik [9.2K]4 years ago
4 0
84+8x=15x+140
Subtract 84 from both sides
8x=15x+56
Subtract 15x from both sides
-7x=56
Divide both sides by -7
x=-8
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Fred paid $75 for a pack of 15 toy mice.<br><br><br> How much did each mouse cost?
morpeh [17]
75 divided by 15 equals 5 so each mouse cost $5.
7 0
3 years ago
Read 2 more answers
Two slits are illuminated by a 348 nm light. The angle between the zeroth-order bright band at the center of the screen and the
Andre45 [30]

Answer:0.369 m

Step-by-step explanation:

Given

Distance between slit and screen is D=154 cm

Wavelength \lambda =348 nm

Angle between zeroth order bright fringe and Fourth-order bright fringe is \theta =13.5^{\circ}

let distance between the slits be d

Distance of n th bright fringe From central Fringe is given by

y_n=\frac{nD\lambda }{d}

Also \tan \theta =\frac{y_4}{D}

y_4=\tan (13.5)\cdot 1.54

y_4=0.24\times 1.54

y_4=0.369 m

5 0
3 years ago
City A is 10 miles from city B and 5 miles from city C. Cities A, B, and C form a right triangle at A. A road connects cities B
laila [671]

Answer:

11.18 miles

Step-by-step explanation:

The sides of a right triangle a, b, c are related by the equation

a^2 + b^2 = c^2

where c is the longest side of the triangle

Hence given that A connects B and C directly and forms a right angle at A

5^2 + 10^2 = c^2

Where c is the length of the road

25 + 100 = c^2

125 = c^2

c = 125^1/2

= 11.18 miles

3 0
3 years ago
In most microcomputers the addresses of memory locations are specified in hexadecimal. These addresses are sequential numbers th
iren [92.7K]

Considering that the addresses of memory locations are specified in hexadecimal.

a) The number of memory locations in a memory address range ( 0000₁₆ to FFFF₁₆ )  = 65536 memory locations

b) The range of hex addresses in a microcomputer with 4096 memory locations is ;  4095

<u>applying the given data </u>:

a) first step : convert FFFF₁₆ to decimal           ( note F₁₆ = 15 decimal )

( F * 16^3 ) + ( F * 16^2 ) + ( F * 16^1 ) + ( F * 16^0 )

= ( 15 * 16^3 ) + ( 15 * 16^2 ) + ( 15 * 16^1 ) + ( 15 * 1 )

=  61440 + 3840 + 240 + 15 = 65535

∴ the memory locations from  0000₁₆ to FFFF₁₆ = from 0 to 65535 = 65536 locations

b) The range of hex addresses with a memory location of 4096

= 0000₁₆ to FFFF₁₆ =  0 to 4096

∴ the range = 4095

Hence we can conclude that the memory locations in ( a ) = 65536 while the range of hex addresses with a memory location of 4096 = 4095.

Learn more : brainly.com/question/18993173

6 0
3 years ago
M∠DEF = __because they are_________
vovikov84 [41]

Answer:

m∠GDE

alternate interior angles

3 0
3 years ago
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