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Alexus [3.1K]
3 years ago
15

I need help with 15/20

Mathematics
2 answers:
Mrac [35]3 years ago
8 0
.75 is the answer because it looks like division
mars1129 [50]3 years ago
8 0
If you want to simplify it it would be 3/4

Find a common factor (5) and divide each number by that to get your simplified fraction!

Hope this helps!
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Pieter wrote and solved an equation that models the number of hours it takes to dig a well to a level of 72 feet below sea level
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Answer:

The answer is B or It must be a positive number since it represents a number of hours.

Step-by-step explanation:

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2 years ago
A quality analyst wants to construct a sample mean chart for controlling a packaging process. He knows from past experience that
rosijanka [135]

Using it's concept, it is found that the sample mean package weight for Thursday is of 19 ounces.

<h3>What is the mean of a data-set?</h3>

The mean of a data-set is given by the <u>sum of the observations divided by the number of observations</u>.

For Thursday, the package weights in ounces are given by: {18, 19, 20, 19}.

Hence, the sample mean in ounces is of:

M = (18 + 19 + 20 + 19)/4 = 19.

More can be learned about the mean concept at brainly.com/question/24628525

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2 years ago
Suppose the line of best fit is being found for some data points that have an r-value of 0.876. If the standard deviation of the
Nezavi [6.7K]
1.129 is the answer i promise 
3 0
3 years ago
Read 2 more answers
find 3 consecutive even integers such that the sum of the smaller 2 is 6 less than twice the largest one
saw5 [17]

n, n + 2, n + 4 - three consecutive even integers

n + 2 = 2(n + 4) - 6     |use distributive property

n + 2 = (2)(n) + (2)(4) - 6

n + 2 = 2n + 8 - 6

n + 2 = 2n + 2     |subtract 2 from both sides

n = 2n       |subtract 2n from both sides

-n = 0

n = 0

n + 2 = 0 + 2 = 2

n + 4 = 0 + 4 = 4

Answer: 0, 2, 4.

6 0
3 years ago
How do we Round with any numbers, (on a number line) ?
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Answer:

round it to the nearest 10th?

Step-by-step explanation:

that's what I do at least.

7 0
2 years ago
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