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3 years ago

Which phrase best describes the translation from the graph y = (x + 2)2 to the graph of y = x2 + 3?

2 answers:

7 0

1. Consider the transformation that maps the graph of the function $y=(x+2)^2$ into the graph of the function $y=x^2.$ This transmormation has a rule:

(x,y)→(x+2,y)

that is translation 2 units to the right.

2. Consider the transformation that maps the graph of the function $y=x^2$ into the graph of the function $y=x^2+3.$ This transformation has a rule:

(x,y)→(x,y+3)

that is translation 3 units up.

Answer: correct choice is C.

saul85 [17]3 years ago

5 0

C looks like the right answer

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I need help bc i dont understand so plz help due tomorrow

alexgriva [62]

Answer:

c = 3 is the only thing i can think of lmk if im wrong..

Step-by-step explanation:

c =3 because 12÷4 (pentagons)= 3

3 0

2 years ago

Can someone answer this question please please answer it correctly I’d it’s correct I will mark you brainliest please help me

AVprozaik [17]

Answer:

6.28

Step-by-step explanation:

Area=πx2^2

Area=4π

Area=4π/2

Area=2π

Area=6.283185307

Area=6.28

3 0

3 years ago

The sum of two consecutive odd intergers is 92

frutty [35]

Answer:

45,47

Step-by-step explanation:

(x)+(x+2)=92

= 2x+2=92

=2x=90

x=45

x+2=47

8 0

3 years ago

Read 2 more answers

A circle with radius of 5 cm sits inside a 11 cm * 11 cm rectangle.

Nadusha1986 [10]

Answer:

42.43 $cm^{2}$

Step-by-step explanation:

Given:

A circle with a radius of 5 cm sits inside a 11 cm x 11 cm rectangle.

Question asked:

What is the area of the shaded region as shown in the figure ?

Solution:

First of all calculate area of circle and then area of rectangle:-

$Area\ of\ cirle=\pi r^{2}$

$=\frac{22}{7} \times5\times5\\ \\ =\frac{550}{7}\\ \\=78.571\ cm^{2}\\$

As here length an width both are 11 cm, we can say that this is a square.

$Area\ of\ square=(Side)^{2}$

$=11\times11=121\ cm^{2}$

Now, area of shaded region = Area of square - Area of circle

= 121 - 78.571 = 42.429 $cm^{2}$

Therefore, the area of the shaded region will be 42.43 $cm^{2}$

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5 0

3 years ago

2564.0 millimeters tall. If the boards are too long they must be trimmed, and if the boards are too short they cannot be used. A

Leokris [45]

Answer:

We conclude that the board's length is equal to 2564.0 millimeters.

Step-by-step explanation:

We are given that a sample of 26 is made, and it is found that they have a mean of 2559.5 millimeters with a standard deviation of 15.0.

Let $\mu$ = population mean length of the board.

So, Null Hypothesis, $H_0$ : $\mu$ = 2564.0 millimeters {means that the board's length is equal to 2564.0 millimeters}

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ 2564.0 millimeters {means that the boards are either too long or too short}

The test statistics that will be used here is One-sample t-test statistics because we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s }{\sqrt{n}} }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean length of boards = 2559.5 millimeters

s = sample standard deviation = 15.0 millimeters

n = sample of boards = 26

So, the test statistics = $\frac{2559.5-2564.0}{\frac{15.0 }{\sqrt{26}} }$ ~ $t_2_5$

= -1.529

The value of t-test statistics is -1.529.

Now, at a 0.05 level of significance, the t table gives a critical value of -2.06 and 2.06 at 25 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the board's length is equal to 2564.0 millimeters.

4 0

3 years ago