Answer:
![\begin{array}{|c|c|c|} \cline{1-3}\text{Time of day} & \text{Frequency} & \text{Angle size}\\\cline{1-3}\text{Morning} & 45 & 180\\\cline{1-3}\text{Afternoon} & 15 & \textbf{60}\\\cline{1-3}\text{Evening} & 30 & \textbf{120}\\\cline{1-3}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7B%7Cc%7Cc%7Cc%7C%7D%20%5Ccline%7B1-3%7D%5Ctext%7BTime%20of%20day%7D%20%26%20%5Ctext%7BFrequency%7D%20%26%20%5Ctext%7BAngle%20size%7D%5C%5C%5Ccline%7B1-3%7D%5Ctext%7BMorning%7D%20%26%2045%20%26%20180%5C%5C%5Ccline%7B1-3%7D%5Ctext%7BAfternoon%7D%20%26%2015%20%26%20%5Ctextbf%7B60%7D%5C%5C%5Ccline%7B1-3%7D%5Ctext%7BEvening%7D%20%26%2030%20%26%20%5Ctextbf%7B120%7D%5C%5C%5Ccline%7B1-3%7D%5Cend%7Barray%7D)
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Explanation:
In the morning, Chris has 45 clients out of 90 total for the week. This represents the fraction 45/90.
Multiply top and bottom by 4 to get to 180/360. I chose 4 because 90*4 = 360.
So that's how your teacher got 180 degrees for the morning angle.
Or you could compute 45/90 = 0.5 and then say 0.5*360 = 180.
The morning clients make up 50% of all his clients.
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For the afternoon, he has 15 clients out of 90.
15/90 = (15/90)*(4/4) = 60/360
I multiplied top and bottom by 4 like last time.
However, this time I got 60 as the numerator.
So a 60 degree angle is used for the afternoon clients.
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In the evening, he has 30 clients to give us the fraction 30/90.
Like before, multiply top and bottom by 4
30/90 = (30*4)/(90*4) = 120/360
We use a 120 degree angle here.