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3 years ago

(21 POINTS) Don't explain answer just put what you got, I'm only comparing answers that's all.

Mathematics

1 answer:

m_a_m_a [10]3 years ago

8 0

Answer:

This may not be that accurate as I am a bit rusty with trigonometry:

tan D: d/f

sin F: f/e

tan F: f/d

cos F: d/e

sin D: d/e

cos D: f/e

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Mathematics <br><br> Solving inequality

lions [1.4K]

Answer:

x _> 9 I dont have the symbol on my phone so I just put the greater than sign there

Step-by-step explanation:

1. Subtract 3 from both sides

5x > 48 - 3

2. simplofy 48 - 3 to 45

5x > 45

3. Divide both sides by 5

x > 45/5

4. Then simplify 45/5 to 9 which gives us the answer

And again I dont have the sign thats why I used the greater than sign

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2 years ago

In what temperature range can mercury be found as a liquid

Varvara68 [4.7K]

Some metals melt at lower temps than others. Tin becomes liquid at 231.8˚C (447.8˚F); at the other end of the spectrum, tungsten has the highest melting point of any metal: 3,422˚C (6,192˚F). Somewhere in the middle is mercury, which stays in a liquid state until its temperature drops to -40.

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2 years ago

Mike pays $285 in rent every week.<br> How much will he pay in rent for the entire year?

sergejj [24]

Answer:

14,820

Step-by-step explanation:

A year has 52 weeks. 285 x 52 = 14820

6 0

1 year ago

Read 2 more answers

A company manufacturing shirts for a department store decides to create a new style of cotton shirt. The company would

RSB [31]

Answer:

can you be more specific of the question so i cam help you:)

Step-by-step explanation:

4 0

3 years ago

Prove that <br><img src="https://tex.z-dn.net/?f=4cot45%20%5E%7B2%7D%20%20-%203tan%20%5E%7B2%7D%2060%20%2B%202sec%20%5E%7B2%7D60

sesenic [268]

Answer:

$4 \cot {}^{2} (45) - 3 \tan {}^{2} (60) + 2 \sec {}^{2} (60) = 3 \\$

$LHS = 4 \cot {}^{2} (45) - 3 \tan {}^{2} (60) + 2 \sec {}^{2} (60) \\$

let us first take a look at the values of the trigonometric ratios given in the question so that we get quite clear about what is to be done.

here ,

$\cot(45) = 1 \\ \\ \tan(60) = \sqrt{3} \\ \\ \sec(60) = 2$

now ,

we just have to plug in the values considering certain other things given in the question and we're done!

so let's start ~

$4(1) {}^{2} - 3( \sqrt{3} ) {}^{2} + 2(2) {}^{2} \\ \\ \dashrightarrow \: 4(1) - 3(3) + 2(4) \\ \\ \dashrightarrow \: 4 - 9 + 8 \\\\ \dashrightarrow \: 12 - 9 \\ \\\dashrightarrow \: 3 = RHS$

hence , proved ~

hope helpful :D

7 0

2 years ago