Answer:
messages me i will explain how to solve if i can
Answer:
The problem:
Find 
if 
,
![h(x)=\sqrt[3]{x+3}](https://tex.z-dn.net/?f=h%28x%29%3D%5Csqrt%5B3%5D%7Bx%2B3%7D)
, and
![f(x)=\sqrt[3]{x+2}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7Bx%2B2%7D)
.
Step-by-step explanation:
Replace 
in with since we are asked to find 
:
![\sqrt[3]{x+3}=\sqrt[3]{g(x)+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B3%7D%3D%5Csqrt%5B3%5D%7Bg%28x%29%2B2%7D)
![\sqrt[3]{x+1+2}=\sqrt[3]{g(x)+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B1%2B2%7D%3D%5Csqrt%5B3%5D%7Bg%28x%29%2B2%7D)
This implies that 
Let's check:
![\sqrt[3]{(x+1)+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%28x%2B1%29%2B2%7D)
![\sqrt[3]{x+1+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B1%2B2%7D)
![\sqrt[3]{x+3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%2B3%7D)
which is the required result for 
.
Answer: 22 double chocolate cookies
Step-by-step explanation:
25 oatmeal raisin
38 sugar cookie
65 chocolate chip
22 double chocolate
De Moivre's theorem uses this general formula z = r(cos α + i<span> sin α) that is where we can have the form a + bi. If the given is raised to a certain number, then the r is raised to the same number while the angles are being multiplied by that number.
For 1) </span>[3cos(27))+isin(27)]^5 we first apply the concept I mentioned above where it becomes
[3^5cos(27*5))+isin(27*5)] and then after simplifying we get, [243 (cos (135) + isin (135))]
it is then further simplified to 243 (-1/ √2) + 243i (1/√2) = -243/√2 + 243/<span>√2 i
and that is the answer.
For 2) </span>[2(cos(40))+isin(40)]^6, we apply the same steps in 1)
[2^6(cos(40*6))+isin(40*6)],
[64(cos(240))+isin(240)] = 64 (-1/2) + 64i (-√3 /2)
And the answer is -32 -32 √3 i
Summary:
1) -243/√2 + 243/√2 i
2)-32 -32 √3 i
