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kipiarov [429]
3 years ago
11

Cargo ships arrive at a loading dock at a rate of 2 per day. The dock has the capability of handling 3 arrivals per day. How man

y days per month (assume 30 days in a month) would you expect the dock being unable to handle all arriving ships? (Hint: first find the probability that more than 3 ships arrive and then use that probability to find the expected number of days in a month too many ships arrive.)
Mathematics
1 answer:
Vsevolod [243]3 years ago
6 0

Answer:

4 days

Step-by-step explanation:

We need to use the probability functions of each of the intervals to know the Probability number and then use it in the expected value.

P(x>3 cargo ships) = 1-P(x<=3)

P(x>3) = 1-P(x<=3)

P(x>3) = 1-[P(x=0)+P(x=1)+P(x=2)+P(x=3)]

P(x>3) = 1 - [\frac{e^{-2}2^0}{01}+\frac{e^{-2}2^1}{11}+\frac{e^{-2}2^2}{21}+\frac{e^{-3}2^3}{31}]

P(x>3) = 1- [0.1353(1+2+2+1.33)]

P(x>3) = 1-0.856

P(x>3) = 0.1431

Als n=30, expected number is

E(x) =30*P(x>3)

E(x) = 30*0.1431

E(x) = 4.293

I expect 4.293 or 4 days per month the block being unable to hanlde all arriving ships

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Answer:

\sf M=\left(-\dfrac{1}{2},0\right)

Step-by-step explanation:

Let (x₁, y₁) = Point A = (-2, 1)

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\sf Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

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6 0
2 years ago
A can of vegetables is 4.5 in. high and has a diameter of 3 in. Find the volume of the can to the nearest tenth of a unit. Use 3
kiruha [24]

Answer:

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Step-by-step explanation:

7 0
2 years ago
(−4 + 5) − (6 + 7) = x x 0
weeeeeb [17]

1

Add the numbers

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−

4

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5

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−

(

6

+

7

)

=

0

({\color{#c92786}{-4}}+{\color{#c92786}{5}})-(6+7)=xx^{0}

(−4+5)−(6+7)=xx0

(

1

)

−

(

6

+

7

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0

({\color{#c92786}{1}})-(6+7)=xx^{0}

(1)−(6+7)=xx0

2

Add the numbers

1

−

(

6

+

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1-({\color{#c92786}{6}}+{\color{#c92786}{7}})=xx^{0}

1−(6+7)=xx0

1

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3

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1-({\color{#c92786}{13}})=xx^{0}

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3

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1

⋅

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3

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1{\color{#c92786}{-1}} \cdot {\color{#c92786}{13}}=xx^{0}

1−1⋅13=xx0

1

−

1

3

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1{\color{#c92786}{-13}}=xx^{0}

1−13=xx0

4

Subtract the numbers

1

−

1

3

=

0

{\color{#c92786}{1-13}}=xx^{0}

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−12=x1

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Solution

−

1

2

=

1

3 0
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geniusboy [140]

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So if the diagram shows arc AB with length 9pi/2 and radius AO with length 6, we can use the formula to compute “Length of an arc” to arrive at the missing angle.

Length of an arc = X/360 x 2pi x radius

Substituting for the known values, our formula can now be re-written as

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(3 x 180)/4 = X

540/4 = X

135 = X

Therefore the central angle that intercepts the arc measures 135 degrees.

6 0
4 years ago
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